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NISA [10]
3 years ago
8

Rank these systems in order of decreasing entropy. Rank from highest to lowest entropy.

Chemistry
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

The answer is "order will be A > F > B> D > G > C > E".

Explanation:

  • Entropy is disunity, the greater the lack of organization the entropy.  
  • When two gases use the same moles, then more entropy is achieved  for a larger number of atoms in the molecule (even with more macrostates).  
  • Its smaller your volume the less the molecules may circulate, reducing as well as the amount of potential different countries and thus the entropy.  
  • Molecules or atoms in colder gas are much less active so they do not actually take so many various energy states and therefore less entropy. In colder gas.  
  • A liquid is requested more so than gas and its randomness decreases.

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It changes the rate of growth that cells usually undergo.
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B is gas


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3 0
3 years ago
Calculate the energy that is required to change 50.0 g ice at -30.0°C to a liquid at 73.0°C. The heat of fusion = 333 J/g, the h
OverLord2011 [107]

Answer:

There is 3.5*10^4 J of energy needed.

Explanation:

<u>Step 1:</u> Data given

Mass of ice at -30.0 °C = 50.0 grams

Final temperature = 73.0 °C

The heat of fusion = 333 J/g

the heat of vaporization = 2256 J/g

the specific heat capacity of ice = 2.06 J/gK

the specific heat capacity of liquid water = 4.184 J/gK

<u>Step 2:</u> Calculate the heat absorbed by ice

q = m*c*(T2-T1)

⇒ m = the mass of ice = 50.0 grams

⇒ c = the heat capacity of ice = 2.06 J/gK = 2.06 J/g°C

⇒ T2 = the fina ltemperature of ice = 0°C

⇒ T1 = the initial temperature of ice = -30.0°C

q = 50.0 * 2.06 J/g°C * 30 °C

q = 3090 J

<u>Step 3:</u> Calculate heat required to melt the ice at 0°C:

q = m*(heat of fusion)

q = 50.0* 333J/g

q =  16650 J

<u> </u>

<u>Step 4</u>: Calculate the heat required to raise the temperature of water from 0°C to 73.0°C

q = m*c*(T2-T1)

 ⇒ mass = 50.0 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = T2-T1 = 73.0 - 0  = 73 °C

q = 50.0 * 4.184 * 73.0 = 15271.6 J

<u>Step 5:</u> Calculate the total energy

qtotal = 3090 + 16650 + 15271.6 = 35011.6 J = 3.5 * 10^4 J

There is 3.5*10^4 J of energy needed.

8 0
3 years ago
Which one of these compounds is an ionic compound? question 18 options: n2 na2o co2?
spayn [35]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For N₂,

                    E.N of Nitrogen      =   3.04

                    E.N of Nitrogen      =   3.04

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For Na₂O,

                    E.N of Oxygen       =   3.44

                    E.N of Sodium       =   0.93

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For CO₂,

                    E.N of Oxygen       =   3.44

                    E.N of Carbon       =    2.55

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                    E.N Difference             0.89         (Polar Covalent)

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3 years ago
What is the concentration in % (v/v) of 175 mL of isopropyl alcohol that is
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Answer:

40/220 ×100=18.6 is all I got I know that by heart so um yea

Explanation:

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