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mafiozo [28]
3 years ago
11

Help plzzzzzzzzzzzzzz

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0
The ratios are not equivalent.

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Please help ASAP and help me find what the value of x is
elixir [45]

Answer:

x=44

Step-by-step explanation:

33+103+x=180

136+x=180

x=44

6 0
4 years ago
Read 2 more answers
The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ
Rudik [331]
This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5)   or approximately
=0.00006181
7 0
4 years ago
15 Points and ill mark brainliest!
natima [27]
Neat
of turf, 83.33333% of the 1050 were minor
so about 875 minor injuries in turf
and 10.857% of 1050 were substantial meaning about 114 substantial
leaving 63 severe field turf
 
meaning 938 minor in gras (totalminior-minorturf=grassminor)
so now we know that grassmionr=938 that that is 1
and hen that is 77.972 gras is mionr so 938=77.972%
1203 total gras
then 4.26 of gras is severe or about 51
and leaving about 217 substantial gras injuries
total them yourself
I have to go sorry bye hope this helped
7 0
3 years ago
UNA POBLACION DE CIERTA CIUDAD EN EL AÑO 2000 ERA DE 250,000 HABITANTES CON UNA TASA DE CRECIMIENTO RELATIVO DEL 2% , DETERMINA
Fofino [41]

Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

      = A*(1.02)*(1.02) = A*(1.02)^2

Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

Sabemos que en t = 0 (el año 2000) la población es 250,000

Entonces A = 250,000

P(t) = 250,000*(1.02)^t

Ahora queremos calcular la población en el año 2012

entonces si t = 0 es el 2000

2012 esta representado con t = 12

Reemplazando eso en la ecuación, obtenemos:

P(12) = 250,000*(1.02)^12 = 317,060.4

Como esto es una población tenemos que redondearlo al próximo número entero, como el primer digito después del punto es 4, redondeamos para abajo.

Entonces la población que se espera para el 2012 es: 317,060

5 0
3 years ago
PLEASE ANSWER ASAP !!!!
klemol [59]
At h=1 y=-2 so -2 hope it helps!
3 0
3 years ago
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