-2(m + 6) + 1 =3 solve for m

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

m = -7

Step-by-step explanation:

Subtract 1 from both sides:

−2 (m + 6) = 3 − 1

−2 (m +6) = 2

Divide both sides by -2:

m + 6= -1

Subtract 6 from both sides:

m = −1 − 6

Simplify -1 - 6 to -7:

m = -7

KiRa [710]3 years ago

6 0

Answer: M=-7

Step-by-step explanation:

-2(m+6)+1=3

subtract 1 from both sides

-2(m+6)=2

divide by negative 2

m+6=-1

subtract 6 from both sides

m=-7

You might be interested in

A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form

andrey2020 [161]

The general form of quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root
=> x = -b + √ b^2 – 4 ac
2a

It is also written as:
=> ax^2 + bx + c = 0

Quadratic equation involves unknown numbers which is x, the numbers which a, b and c are called coeffecients.
There are also quadratic factorization where you factor the polynomial give to be able to get the value of the equation.

5 0

3 years ago

Read 2 more answers

The equation of line m is 3x−5y=−4.

a_sh-v [17]

I line that is perpendicular is a line with reversed slopes like 2/1 is perpendicular to -1/2. So find the slope by getting the y by itself and reverse it. Remember to switch the signs too! P.S. if you don't know how to get the y by itself just take and subtract 3x from -5y and -4 then divide by 5. Hope I helped!

8 0

2 years ago

Indicate a general rule for the nth term of the sequence a1 = 2 and r = √3.

pantera1 [17]

It is given in the question that,

$a_{1} = 2, r = \sqrt 3$