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2 years ago

The area of a square sandbox is 46 ft.². The nearest foot what is the perimeter of the sandbox?

Mathematics

1 answer:

AlexFokin [52]2 years ago

4 0

It is given in the question that

The area of a square sandbox is 46 ft.².

Let the length of the side of the square sandbox is x ft .

And formula of area of square is

$Area = side^2$

Substituting the given value of area

$46 = side^2$

We need to get rid of square, and for that we take square root on both sides

$\sqrt{46}=side$

And the formula of perimeter of square is

$Perimeter=4*side$

$Perimeter=4\sqrt{46}=27ft$

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Juwan collects 36 pieces of candy while trick-or-treating. He eats one-third of them and gives a fourth of whats left away. How

Nady [450]

Answer:

18 candies.

Step-by-step explanation:

Given:

Juwan collects 36 pieces of candy while trick-or-treating.

He eats one-third of them and gives a fourth of whats left away.

<u>Question asked:</u>

How many candies does he still have?

<u>Solution:</u>

Total candies collected by Juwan = 36

Candies eaten by Juwan = $\frac{1}{3} \ of \ 36=\frac{1}{3} \times36=12\ candies$

Remaining candies = 36 - 12 = 24

Candies given by her = $\frac{1}{4}\ of\ 24= \frac{1}{4}\times24=6\ candies$

Remaining candies = 24 - 6 = 18 Candies.

Thus, he still have 18 candies.

6 0

2 years ago

Write annequivalent fraction by multiplying 2/3

STatiana [176]

$\bf \cfrac{2}{3}\cdot \cfrac{same}{same}\implies \stackrel{equivalent~fraction}{\cfrac{2(same)}{3(same)}}\qquad therefore\qquad \cfrac{2}{3}\cdot \cfrac{9}{9}\implies \stackrel{equivalent}{\cfrac{18}{27}}$

3 0

3 years ago

Tell weather the lines through the given points are parallel perpendicular or neither

Ann [662]

Answer:

a) Slope of line 1 = (2/3)

b) Slope of line 2 = (-3/2)

c) Two lines are perpendicular.

Step-by-step explanation:

Here, let the points of line 1 are A(1,0) and B(7,4)

Let the points of line 2 are A(7,0) and B(3,6)

Now for any two points, the slope m of the line is given as :

$m = \frac{y_2 - y_1}{x_2-x_1}$

⇒Slope of the line AB = $m1 =( \frac{4-0}{7-1}) = \frac{4}{6} = \frac{2}{3}$

or, m1 = 2/3

and Slope of the line PQ = $m2 =( \frac{6-0}{3-7}) = -\frac{6}{4} = -\frac{3}{2}$

or, m2 = -3/2

Now, TWO LINERS ARE SAID TO BE PERPENDICULAR if

m1 x m2 = -1 :with heir respective slope m1 and m2

Here, $m1 \times m2 = \frac{2}{3} \times \frac{-3}{2} = -1$

⇒ SLOPE OF AB x SLOPE OF PQ = -1

Hence, Line AB is perpendicular to the line PQ.

5 0

2 years ago

PLEASE HELP ME!!!!!!!!

Hoochie [10]

Option C: $64 \ cm^2$ is the area of the composite figure.

Explanation:

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

$b_1=10 \ cm$

$b_2=6 \ cm$ and

$h=4 \ cm$

Area of the trapezoid = $\frac{1}{2} (b_1+b_2)h$

Substituting the values, we get,

$A=\frac{1}{2} (10+6)4$

$A=\frac{1}{2} (16)4$

$A=32 \ cm^2$

Thus, the area of one trapezoid is $32 \ {cm}^{2}$

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ $= 64 \ cm^2$

Thus, the area of the composite figure is $64 \ cm^2$

Hence, Option C is the correct answer.

3 0

2 years ago

Help me plssssssssssssssssssssa

jolli1 [7]

Answer:

i believe the answer is A.

Step-by-step explanation: Because the angle PQS is not a 90 degree angle it should equal 180 degrees, it is now lowered down to the answers A. and B. Answer B. has 2x and answer A. has just x. if it were to be 2x then the x would have to represent 30 degrees but the point plotted x does not equal 30 degrees therefore leaving the last answer as A. x-60=180

8 0

2 years ago