Answer:
h=18.05 cm
Explanation:
Given that
m= 25 kg
K= 1300 N/m
x=26.4 cm
θ= 19.5 ∘
When the block just leave the spring then the speed of block = v m/s
From energy conservation
![\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DKx%5E2%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![Kx^2=mv^2](https://tex.z-dn.net/?f=Kx%5E2%3Dmv%5E2)
![v=\sqrt{\dfrac{kx^2}{m}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7Bkx%5E2%7D%7Bm%7D%7D)
By putting the values
![v=\sqrt{\dfrac{kx^2}{m}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7Bkx%5E2%7D%7Bm%7D%7D)
![v=\sqrt{\dfrac{1300\times 0.264^2}{25}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7B1300%5Ctimes%200.264%5E2%7D%7B25%7D%7D)
v=1.9 m/s
When block reach at the maximum height(h) position then the final speed of the block will be zero.
We know that
![V_f^2=V_i^2-2gh](https://tex.z-dn.net/?f=V_f%5E2%3DV_i%5E2-2gh)
By putting the values
![0^2=1.9^2-2\times 10\times h](https://tex.z-dn.net/?f=0%5E2%3D1.9%5E2-2%5Ctimes%2010%5Ctimes%20h)
h=0.1805 m
h=18.05 cm
Answer:
Yes, when an apple falls towards the earth, the apple gets accelerated and comes down due to the gravitational force of attraction used by the earth. The apple also exerts an equal and opposite force on the earth but the earth does not move because the mass of the apple is very small, due to which the gravitational force produces a large acceleration in it (a = F/m) but the mass of the earth is very large, the same gravitational force produces very small acceleration in the earth and we don't see the earth rising towards the apple.
Answer:
Its diameter increases as it flows down from the pipe. Assuming laminar flow for the water, then Bernoulli's equation can be applied.
P1-P2 + (rho)g(h1 - h2) + 1/2(rho)(v1² - v2²) = 0
Explanation:
P1 = P2 = atmospheric pressure so, P1 - P2 = 0
h1 is greater than h2 so h1-h2 is positive. Rearranging the equation above 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho = v2²
From the continuity equation for fluids
A1v1 = A2v2
v2 = A1v1/A2
Substituting into the equation above
(A1v1/A2)² = 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho
Making A2² the subject of the formula,
A2² = (A1v1)²× rho/(2{ (rho)g(h1-h2) + 1/2(rho)v1²}
The denominator will be greater than the numerator and as a result the diameter of the flowing stream decreases.
Thank you for reading.
If the corner is rounded and is perfectly circular, then the acceleration is centripetal and is always directed toward the center.
Answer:
The "butterfly Effect"
Explanation:
The "butterfly effect" will probably have big changes in the future.