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KengaRu [80]
3 years ago
5

Derek runs 4 laps around the track. If each lap around the track is 0.25 miles long, and he starts and stops in the same locatio

n, what is Derek's displacement?
Physics
2 answers:
trapecia [35]3 years ago
6 0
Derek's displacement is 0 miles, because he starts and stops in the same place. The distance he covered would be 1 mile.

Distance is the total length covered.
Displacement is the distance between the starting point and the end point. If Derek started and stopped in the same place, he had a displacement of 0.

Hope this helps!
Sergeeva-Olga [200]3 years ago
5 0
1.00 1 mile      1 mile 1.00
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3 years ago
it takes 90 j of work to stretch a spring 0.2 m from its equilibrium position. How muc work is needed to stretch it an additiona
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Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring from the equilibrium position

In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

k=\frac{2E}{x^2}=\frac{2(90)}{(0.2)^2}=4500 N/m

Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

x = 0.2 + 0.4 = 0.6 m

Substituting,

E'=\frac{1}{2}kx^2=\frac{1}{2}(4500)(0.6)^2=810 J

Therefore, the additional work needed is

\Delta E=E'-E=810-90=720 J

Learn more about work:

brainly.com/question/6763771

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3 years ago
Rama's weight is 4okg: She is carrying a load of 20kg up to a height of 20 meters.what work does she do?Also mention its type of
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mark me

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