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KengaRu [80]
3 years ago
5

Derek runs 4 laps around the track. If each lap around the track is 0.25 miles long, and he starts and stops in the same locatio

n, what is Derek's displacement?
Physics
2 answers:
trapecia [35]3 years ago
6 0
Derek's displacement is 0 miles, because he starts and stops in the same place. The distance he covered would be 1 mile.

Distance is the total length covered.
Displacement is the distance between the starting point and the end point. If Derek started and stopped in the same place, he had a displacement of 0.

Hope this helps!
Sergeeva-Olga [200]3 years ago
5 0
1.00 1 mile      1 mile 1.00
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If a sheep is running at 3.0 m/s with a mass of 60 kg what is its kinetic energy​
borishaifa [10]

Answer:270joules

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KE = 1/2(60kg)(3.0)^2 = 270 Joules

8 0
3 years ago
Two simple pendulum of slightly different length , are set off oscillating in step is a time of 20s has elasped , during which t
adell [148]

Answer:

Length of longer pendulum = 99.3 cm

Length of shorter pendulum = 82.2 cm

Explanation:

Since the longer pendulum undergoes 10 oscillations in 20 s, its period T = 20 s/10 = 2 s.

From T = 2π√(l/g), the length of the pendulum. l = T²g/4π²

substituting T = 2s and g = 9.8 m/s² we have

l = T²g/4π²

= (2 s)² × 9.8 m/s² ÷ 4π²

= 39.2 m ÷ 4π²

= 0.993 m

= 99.3 cm

Now, for the shorter pendulum to be in step with the longer pendulum, it must have completed some oscillations more than the longer pendulum. Let x be the number of oscillations more in t = 20 s. Let n₁ = number of oscillations of longer pendulum and n₂ = number of oscillations of longer pendulum.

So, n₂ = n₁ + x. Also n₁ = t/T₁ and n₂ = t/T₂ where T₂ = period of shorter pendulum.

t/T₂ = t/T₁ + x

1/T₂ = 1/T₁ + x  (1)

Also, the T₂ = t/n₂ = t/(n₁ + x)  (2)

From (1) T₂ = T₁/(T₁ + x) (3)

equating (2) and (3) we have

t/(n₁ + x) = T₁/(T₁ + x)

substituting t = 20 s and n₁ = 10 and T₁ = 2s, we have

20 s/(10 + x) = 2/(2 + x)

10/(10 + x) = 1/(2 + x)

(10 + x)/10 = (2 + x)

(10 + x) = 10(2 + x)

10 + x = 20 + 10x

collecting like terms

10x - x = 20 - 10

9x = 10

x = 10/9

x = 1.11

x ≅ 1 oscillation

substituting x into (2)

T₂ = t/n₂ = t/(n₁ + x)

= 20/(10 + 1)

= 20/11

= 1.82 s

Since length l = T²g/4π²

substituting T = 1.82 s and g = 9.8 m/s² we have

l = T²g/4π²

= (1.82 s)² × 9.8 m/s² ÷ 4π²

= 32.46 m ÷ 4π²

= 0.822 m

= 82.2 cm

6 0
2 years ago
A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for s
asambeis [7]

Answer:

I=0.0987kg.m^2

Explanation:

From the question we are told that:

Mass M=1.80kg

Deviation d=0.250

Time t=0.940s

Generally the equation for moment of inertia is mathematically given by

 I=\frac{T}{2\pi}^2(mgd)

 I=\frac{0.94}{2.3.142}^2(1.80*9.8*0.250)

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5 0
3 years ago
What type of wave did you create when you pushed your arm back and forth?<br><br> plz help
IgorC [24]

Answer: It is a transverse wave ^^

Explanation:

8 0
2 years ago
You are given two objects of identical size, one made of aluminum and the other of lead. You hang each object separately from a
ollegr [7]

Answer:

Explanation:

Volume of lead object = volume of aluminium object = V

mass of lead object > mass of aluminium object

When both the objects immersed in water, the buoyant force acting on both the objects.

Buoyant force = Volume immersed  x density of water x gravity

As the volume of both the objects is same, so the buoyant force acting on both the objects is same.

So, weight in air of lead object is more than the weight in air of aluminium object.  

7 0
2 years ago
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