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Harrizon [31]
3 years ago
15

What is the time required for sound to travel 1.75 km if the temp of the air is 20 C°?

Physics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

Explanation:

The 2 equations we need for this are

v=331.5+.606T and

d = rt. First we need to find the velocity using the first equation, then we will plug it into the distance equation as the rate to find the time.

v = 331.5 + .606(20.0) I used 3 sig figs for the temp instead of the 1 found in 20.

v = 331.5 + 12.1 so

v = 343.6 m/s

Now, before we can find the time in seconds, we need to convert the distance to meters.

1.75 km = 1750 m:

1750 = 343.6t so

t = 5.09 seconds

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Who is Janna Levin:
viva [34]

Answer:

Janna levin is a cosmologist and professor at physics.

She is an american by race

She was the presenter of Nova feature Black hole Apocalypse and has writtenany science non-fiction books

www.jannalevin.com is her own page where u get her correct info and bio

8 0
4 years ago
A person is lifting a bag of groceries with a uniform force of 75.0 N upward for 2.50 s. They raised the bag 1.50 m to place on
Crank

Answer:

45 W

Explanation:

First of all, we need to find the work done by the person to lift the bag. The work done is given by

W=Fd

where

F = 75.0 N is the force applied

d = 1.50 m is the displacement of the bag

Substituting numbers into the formula,

W=(75.0 N)(1.5 m)=112.5 J

Now we can find the power used, which is given by

P=\frac{W}{t}

where

t = 2.50 s is the time taken

Again, using W=112.5 J, we find

P=\frac{112.5 J}{2.5 s}=45 W

7 0
3 years ago
Question 1 of 20
ad-work [718]

Answer

D. move a small magnet back and forth within a section of the coiled wire.

Explanation:

i put that for the test and i got it right

8 0
3 years ago
Read 2 more answers
A Ping-Pong ball has a diameter of 2.55 cm and average density of 0.116 g/cm3 . What force would be required to hold it complete
Mrac [35]

Answer:

F = 0.075 N

Explanation:

given,

diameter of ping pong ball = 2.55 cm

average density of the ball = 0.116 g/cm³

Force require to hold the ball completely submerged= ?

Volume of the ball

V = \dfrac{4}{3} \pi r^3

V = \dfrac{4}{3} \pi (\dfrac{2.55}{2})^3

    V = 8.63 cm³

density of water = 1 g/cm³

force required to keep the ball submerged is equal to

F = \rho_w V_w g - \rho_b V g

F = 1\times 8.63\times g - 0.116 \times 8.63 \times g

F = 7.63 x 9.8 x 10⁻³

F = 0.075 N

Force required to keep the ball inside the water is equal to 0.075 N

7 0
4 years ago
la potencia mecánica, si Carlos realiza un trabajo de 95 J al subir un objeto del suelo a la mesa en un tiempo de 9 segundos.
irga5000 [103]

Answer:

P = 10,56 Watts

Explanation:

La formula de la potencia es:

P = W/t

donde P es la potencia, W el trabajo realizado y t el tiempo transcurrido.

Reemplazando los valores dados obtengo:

P = 95 J / 9 seg

P = 10,56 Watts

4 0
4 years ago
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