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2 years ago

What is the time required for sound to travel 1.75 km if the temp of the air is 20 C°?

Physics

1 answer:

murzikaleks [220]2 years ago

7 0

Answer:

Explanation:

The 2 equations we need for this are

$v=331.5+.606T$ and

d = rt. First we need to find the velocity using the first equation, then we will plug it into the distance equation as the rate to find the time.

v = 331.5 + .606(20.0) I used 3 sig figs for the temp instead of the 1 found in 20.

v = 331.5 + 12.1 so

v = 343.6 m/s

Now, before we can find the time in seconds, we need to convert the distance to meters.

1.75 km = 1750 m:

1750 = 343.6t so

t = 5.09 seconds

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To suck lemonade of density 1040 kg/m3 up a straw to a maximum height of 4.94 cm, what minimum gauge pressure (in atmospheres) m

Lady bird [3.3K]

Answer:

The minimum gauge pressure is 0.4969 atm.

Explanation:

Given that,

Density = 1040 kg/m³

Height = 4.94 cm

We need to calculate the pressure

Using formula of pressure

$P_{g}=\rho g h$

Where, $\rho$ =density

h = height

Put the value into the formula

$P_{g}=1040\times9.8\times4.94$

$P_{g}=50348.48\ Pa$

Pressure in atmospheres

$1\ atm =101.3\ kPa$

$P_{g}=\dfrac{50348.48}{101325}$

$P_{g}=0.4969\ atm$

Hence, The minimum gauge pressure is 0.4969 atm.

7 0

3 years ago

Read 2 more answers

How many valence electrons are in alkali metals

tatuchka [14]

If you look on the periodic table you will see the top group elements depending on how the elements relate to each in the column. All of the elements in that column show they all have 1 electron in their valence shell. Some of the chemicals in that family or group are Sodium, Lithium, Potassium. The are very reactive because they only have one electron and what 7 more to become stable.

8 0

3 years ago

A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph

Marina86 [1]

Solution:

initial sphere mvr = final sphere mvr + Iω
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m²
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω
where: ω = 2.87 rad/s

So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)²
E = 12.64 J becomes PE = mgh, so
12.64 J = 2.3 kg * 9.8m/s² * h
h = 0.29 m

h = L(1 - cosΘ) → where here L is the distance to the CM
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ
Θ = arccos((1-0.29)/1) = 44.77 º

8 0

3 years ago

A diver jumps from a high platform and stays in the air for 1 second. How high was the platform?

ivolga24 [154]

Answer: Depends

Explanation:

Depends on how much the diver weighs.

6 0

2 years ago

What evidence supports the conclusion that a chemical reaction has occurred?

GalinKa [24]

Answer:

Precipitation formed

Temperature change

fizzing and hissing

bubbles

change in state

Explanation:

3 0

2 years ago