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Lina20 [59]
3 years ago
6

Alpha particles are helium nuclei. electromagnetic waves. electrons. neutrons.

Chemistry
1 answer:
Firdavs [7]3 years ago
4 0
Alpha particles are helium nucleus ! so answer is A !

it is made by ionization of helium, when both the electrons are out , then two unit of positive charge is one helium and thus called alpha particle !
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Chemicals that are able to slow or stop the reaction rate are inhibitors. reactants. products. catalysts.
erma4kov [3.2K]

Answer:inhibitors

Explanation:

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Any two properties of ethane​
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Answer:

colorless odorless gas

two carbon atoms

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What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr
Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

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#1: The element that loses electrons in a chemical reaction is said to have been which of the following?
Mrrafil [7]
#1: The element that loses electrons in a chemical reaction is said to have been which of the following? A. reduced

B. oxidized

C. combusted

D. rusted

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Which type of reaction occurs if one element gains electrons and another loses electrons?

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#3: What is the oxidation number for phosphorus in H4P2O7?

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is that right??

Right

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5 0
3 years ago
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Ulfur dioxide gas can react in the presence of oxygen and vanadium(V) oxide to form sulfur trioxide. Sulfur trioxide is the only
LenaWriter [7]

According to the illustration, the vanadium (V) oxide would be a catalyst.

<h3>What are catalysts?</h3>

Catalysts are substances that are utilized in reactions that are not themselves consumed in reactions but only speed up the rate of the reactions.

Catalysts speed up the rate of reactions by lowering the activation energy of the reactants.

Sulfur dioxide reacts with oxygen to produce sulfur trioxide. The vanadium (v) oxide is not consumed in the reaction. Thus it only serves as a catalyst.

More on catalysts can be found here: brainly.com/question/12260131

#SPJ1

4 0
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