At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
<h3>What is Henry's Law ?</h3>
Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.
<h3>What is relationship between Henry's Law constant and Solubility ?</h3>
The solubility of gas is directly proportional to partial pressure.
It is expressed as:

where,
= Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now put the values in above expression we get

0.080M =
× 1.7 atm

= 0.047 M/atm
Now we have to find the partial pressure of He

0.200 M = 0.047 M/atm × 

= 4.25 atm
Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
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Answer:
A, new substance is formed with different properties
Explanation:
The displacement affect the amount of work done by the fact that more displacement implies more work.
Option B
<u>Explanation:</u>
Work can be defined as the "measure of energy transfer" that occurs when an object is moved over a distance by an external force which is applied in the "direction of the displacement".
Work can be formulated as,

From the above-mentioned formula, we can infer that Work is directly proportional to the displacement of the object.Therefore, more the work is more will be its displacement.
Answer:
CH3
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CH3- C H -CH2-CH2- CH - CH2-CH2-CH3
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CH
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CH3 CH3
Explanation:
Octan
C-C-C-C-C-C-C-C
Metyl
CH3 -
Isopropyl
CH3
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- CH
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CH3
2-metil-5-isopropiloctan
CH3
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CH3- C H -CH2-CH2- CH - CH2-CH2-CH3
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CH
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CH3 CH3
The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.
Describe reagents.
A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.
With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.
In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.
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