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MrMuchimi
3 years ago
9

___________ minerals are dark-colored because they contain _____________. a. Mafic; iron and/or magnesium b. Felsic; iron and/or

magnesium c. Mafic; calcium, sodium, or potassium d. Felsic; calcium, sodium, or potassium
Chemistry
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

A. Mafic; iron and/or magnesium

Explanation:

Let's find the answer by naming some minerals and their chemistry.

Mafic minerals are dark-colored whereas felsic minerals are light-colored, thats way mafic rocks are dark-colored because they are mainly composed by mafic minerals and the other way around for felsic rocks.

But remember that mafic minerals as amphiboles, pyroxenes or biotites, involve in their chemical structure iron and/or magnesium. Although calcium and sodium can be incorporated in amphiboles and clinopyroxenes, they are not involved in orthopyroxenes and biotites. On the other hand, although potassium is involved in biotite and in some extent in amphiboles, this element is not involved in pyroxenes.

So in conclusion, mafic minerals are usually dark-colored because they involve iron and/or magnesium in their chemical structures.  

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The activation energy of an endothermic reaction
yarga [219]

Answer:

The activation energy of an endothermic reaction

A) must be greater than the required △H

Explanation:

endothermic reaction : Are those which absorbs heat from the surrounding

.<em>This energy provide activation energy for the reaction to occur</em>.

So activation energy becomes more than enthalpy.

7 0
4 years ago
Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−]
Arlecino [84]

Answer:

A. 0.000128 M is the solubility of M(OH)2 in pure water.

B. 3.23\times 10^{-6} M is the solubility of M(OH)_2 in a 0.202 M solution of M(NO_3)_2.

Explanation:

A

Solubility product of generic metal hydroxide = K_{sp}=8.45\times 10^{-12}

M(OH)_2\rightleftharpoons M^{2+}+2OH^-

                      S         2S

The expression of a solubility product is given by :

K_{sp}=[M^{2+}][OH^-]^2

K_{sp}=S\times (2S)^2=4S^3

8.45\times 10^{-12}=4S^3

Solving for S:

S=0.000128 M

0.000128 M is the solubility of M(OH)2 in pure water

B

Concentration of M(NO_3)_2 = 0.202 M

Solubility product of generic metal hydroxide = K_{sp}=8.45\times 10^{-12}

M(OH)_2\rightleftharpoons M^{2+}+2OH^-

                   S          2S

So, [M^{2+}]=0.202 M+S

The expression of a solubility product is given by :

K_{sp}=[M^{2+}][OH^-]^2

8.45\times 10^{-12}=(0.202 M+S)(2S)^2

Solving for S:

S=3.23\times 10^{-6} M

3.23\times 10^{-6} M is the solubility of M(OH)_2 in a 0.202 M solution of M(NO_3)_2.

8 0
4 years ago
9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life (t_{1/2}), in minutes:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m(t) = 7.5\,g, m_{o} = 120\,g and t_{1/2} = 3.053\,min, then the time taken by the isotope is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

\tau \approx 4.405\,min

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)

t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
3 years ago
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Answer:

it is probably acrylic or latex

Explanation:

3 0
3 years ago
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e-lub [12.9K]

Answer:

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