Answer:
The final volume will be 24.7 cm³
Explanation:
<u>Step 1:</u> Data given:
Initial temperature = 180 °C
initial volume = 13 cm³ = 13 mL
The mixture is heated to a fina,l temperature of 587 °C
Pressure and amount = constant
<u>Step 2: </u>Calculate final volume
V1/T1 = V2/T2
with V1 = the initial volume V1 = 13 mL = 13*10^-3
with T1 = the initial temperature = 180 °C = 453 Kelvin
with V2 = the final volume = TO BE DETERMINED
with T2 = the final temperature = 587 °C = 860 Kelvin
V2 = (V1*T2)/T1
V2 = (13 mL *860 Kelvin) /453 Kelvin
V2 = 24.68 mL = 24.7 cm³
The final volume will be 24.7 cm³
Answer: The heat of reaction (ΔHrxn) for the reaction is -164.9kJ
Explanation:
The given balanced chemical reaction is,
To calculate the enthalpy of reaction 
.
![\Delta H^o=[n_{CaCl_2}\times \Delta H_f^0_{(CaCl_2)}+n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{CaCO_3}\times \Delta H_f^0_{(CaCO_3)+n_{HCl}\times \Delta H_f^0_{(HCl)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BCaCl_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CaCl_2%29%7D%2Bn_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CO_2%29%7D%2Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2O%29%7D%5D-%5Bn_%7BCaCO_3%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CaCO_3%29%2Bn_%7BHCl%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28HCl%29%7D%5D)
where,
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times -877.1)+(1\times -393.51)+(1\times -285.8)]-[(1\times -1206.9)+(2\times -92.30)]=-164.9kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20-877.1%29%2B%281%5Ctimes%20-393.51%29%2B%281%5Ctimes%20-285.8%29%5D-%5B%281%5Ctimes%20-1206.9%29%2B%282%5Ctimes%20-92.30%29%5D%3D-164.9kJ)
Therefore the heat of reaction (ΔHrxn) for the reaction is -164.9kJ
Answer:
semipermeability
Explanation:
partially but not freely or wholly permeable specifically : permeable to some usually small molecules but not to other usually larger particles a semipermeable membrane.
Answer:
Examples of isotones include carbon-12, nitrogen-13 and oxygen-14. These atoms all have six neutrons and six, seven and eight protons respectively. A mnemonic that can be used to differentiate isotones from isotopes and isobars is as follows: same Z (number of protons) = isotopes.
Answer:
you can tell diorite is an intrusive igneous rock because it has a coarse-grained texture
