Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
<span> It requires much more energy to vaporize the substance than to melt it</span>
Answer:
is the correct answer to the given question.
Explanation:
Given k=6.40 x 10-3 min-1.
According to the first order reaction .
The concentration of time can be written as
![[\ A\ ]\ = \ [\ A_{0}\ ] * e \ ^\ {-kt}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D%5C%20%3D%20%5C%20%5B%5C%20%20A_%7B0%7D%5C%20%5D%20%20%2A%20e%20%5C%20%5E%5C%20%20%7B-kt%7D)
Here ![[\ A\ ]_{0}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D)
= Initial concentration.
So ![[\ A\ ]_{0}= 0.0314 M](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D%3D%200.0314%20M)
Putting this value into the above equation.
=0.211 M
This can be written as
Secondary consumers in a food web are carnivores that feed on primary consumers. Consumers are organisms that receive energy by eating other organisms. Specifically, primary consumers are those that feed on producers. Producers are those that are able to produce their own food, like plants. Meanwhile, secondary consumers, like humans, eat primary consumers such as cows.
Answer:
planets,meteoroids and asteroids
Explanation:
