The force machines exert on objects are output forces.
Answer:
final temperature is 364.32 K
mass of air is 0.5423 kg
Explanation:
given data
pressure p1 = 380 kPa
volume v1 = 0.120 m³
temperature = 20°C = 20 + 273 = 293 K
pressure p2 = 3450 kPa
volume v2 = 5% increase
to find out
final temperature and the mass
solution
we consider here ideal gas
so equation is
p1v1 / t1 = p2v2/t2
put here all value and find t2
and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³
so
t2 = p2v2/ p1v1 × t1
t2 = (450 × 0.126) / (380 × 0.120) × 293
t2 = 364.32 K
so final temperature is 364.32 K
and
mass = p2v2 / Rt2
here R gas constant is 0.287 kJ/kg.K
so
mass = (450 × 0.126) / (0.287 × 364.32 )
mass = 0.5423
so mass of air is 0.5423 kg
Answer: 
Explanation:
Given
the height of the tank is 
The diameter of the tank is 
Density of solution 
Water pressure at the bottom of the tank is
Answer:
(a) 8 m/s
(b) 5 s
Explanation:
(a)
Using,
V² = U²+2gh ......................... Equation 1
Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.
Given: V = 0 m/s ( At it's maximum height), g = -1.6 m/s² ( as its moves against gravity), h = 20 m.
Substitute into equation 1
0 = U²+[2×20×(-1.6)]
-U² = - 64
U² = 64
U = √64
U = 8 m/s.
(b)
V = U +gt.................... Equation 2
Where t = time to reach the maximum height.
Given: V = 0 m/s ( At the maximum height), g = -1.6 m/s² ( Moving against gravity), U = 8 m/s.
Substitute into equation 2
0 = 8+(-1.6t)
-8 = -1.6t
-1.6t = -8
t = -8/-1.6
t = 5 s.
