In the reaction of sodium with bromine, explain which atom is reduced.

Chemistry

1 answer:

atroni [7]4 years ago

4 0

Answer:

The reduced atom is Br.

Explanation:

The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).

The oxidation process is the process in which electrons are lost and produce positively charged ions.

The reduction process is the process in which electrons is gained and negatively charge ions are produced.

In the reaction of chlorine with calcium:

2Na + Br₂ → 2NaBr,

Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).

Br₂ gains 2 electrons and is reduced to 2Br⁻. (Br₂ + 2e → 2Br⁻).

So, the reduced atom is Br.

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Calculate the pH of a solution formed by dissolving 0.040 moles of solid sodium lactate, NaC3H5O3, in 50.0 mL of 1.0 M HC3H5O3.

natima [27]

The pH of the solution is 3,76

Why?

To solve this problem we have to apply the Henderson-Hasselbach equation, which is used whenever we need to calculate the pH of a solution of an acid HA (Lactic Acid) and its conjugate base A⁻ (Sodium Lactate)

We can use either moles or concentrations for this equation. In this case, we are going to use the moles, and we are going to take the pKa of lactic acid as 3,86:

$pH=pKa+log(\frac{nA^- }{nHA} )=3,86+log(\frac{(0,04moles)}{(0,05mL)*(1.0M)} )\\\\pH=3,76$