4 years ago

Perform the following operation

Chemistry

1 answer:

pantera1 [17]4 years ago

5 0

Answer:

6.48 x 10^5

Explanation:

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2. How many grams of water can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories?

sertanlavr [38]

Answer:

672 g

Explanation:

We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.

$Q = c \times m \times \Delta T$

where,

c: specific heat of the water

m: mass

ΔT: change in the temperature

$m = \frac{Q}{c \times \Delta T } = \frac{8,064cal}{(1cal/g. \° C) \times (37.0 \° C - 25.0 \° C) } = 672 g$

The mass of water that can be warmed under these conditions is 672 grams.

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C. tornado is your answer

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3 years ago

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2) What is the specific heat of a metal if 202 J is required to heat 44.0 g of the metal from 22.0°C to

eimsori [14]

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4 years ago

The atomic number of an element that has 9 protons 9 electrons and 10 neutrons is?

natali 33 [55]

Answer:

nor its just

Explanation:

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3 years ago

Question 5

yuradex [85]

Answer:

it will have 1 valence electron as its in the first group in the periodic table.

It will lose electrons as its easier.

The charge will be 1+ as it lost 1 .

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3 years ago