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JulijaS [17]
3 years ago
10

A piano string having a mass per unit length equal to 5.20 10-3 kg/m is under a tension of 1 450 N. Find the speed with which a

wave travels on this string.
Physics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

The wave in the string travels with a speed of 528.1 m/s

Explanation:

Wave speed of sound waves in a string, v, is related to the Tension in the string, T, and the mass per unit length, μ, by the relation,

v = √(T/μ)

μ = 5.20 × 10⁻³ kg/m

T = 1450N

v = √(1450/0.0052) = 528.1 m/s

Hope this Helps!!!

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Two small objects each with a net charge of Q (positive) exert a force of magnitude F on each other. We replace one of the objec
erik [133]

Answer:

option B

Explanation:

we know,

Force between two charge is calculated by

F = \dfrac{kq_1q_2}{r^2}

r is the distance between the two charges

k is Coulomb constant.

give two small object with charge Q

now, Force

F = \dfrac{kQQ}{r^2}......(1)

now,

New force if another charge is equal to 4 Q

F' = \dfrac{kQ(4Q)}{r^2}

F' = 4\dfrac{kQQ}{r^2}

now from equation 1

F' = 4 F

Hence, the correct answer is option B

5 0
3 years ago
If we assume that the metallic plates are perfect conductors, the electric field in their interiors must vanish. given that the
Svetlanka [38]

here the charge density of metal plate is given as

charge density = \sigma

now the electric field is given Gauss law

\int E. dA = \frac{q}{\epsilon_0}

now here E = constant

so we will have

E. \int dA = \frac{q}{\epsilon_0}

Since total area on both sides of plate will be double and becomes 2A

E. 2A  = \frac{q}{\epsilon_0}

E = \frac{q/A}{2\epsilon_0}

E = \frac{\sigma}{2\epsilon_0}

Now if we will find the electric field inside the metal plate

Then as we know that total charge inside the plate will always be zero

so we have

E = 0

7 0
3 years ago
A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30^\circ30 ​∘ ​​ with the horizontal. What is
Nastasia [14]

Answer:

Explanation:

Since the surface is frictionless therefore there will be no friction force on block but there will be weight of block which we can divide in to two components i.e. mgcosθ &mgsinθ which is perpendicular and parallel to the surface respectively.

In response to mgcosθ ramp will apply a normal force to the block which will be of equal magnitude to that of mgcosθ.

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7 0
3 years ago
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l
goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

\Delta t = \frac{0.18\ m}{340\ m/s}

<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>

4 0
3 years ago
Thermal Conductors don't have to be hot to transfer heat, explain a situation when a ice cube would still transfer heat to anoth
barxatty [35]
An ice cube would transfer heat to another object whose temperature
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If you could find a block of solid nitrogen, its temperature would be
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6 0
4 years ago
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