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3 years ago

Which sections of the heating curve illustrate this process?

Physics

1 answer:

kirill115 [55]3 years ago

5 0

Answer:

B followed by D

Explanation:

The heat energy absorbed at B goes into potential energy that breaks the inter-molecular bonds and thus the constant temperature. Once the molecules have gained enough energy they escape the closely bonded structure and thus are free to move in random directions due to high kinetic energy. At this point (part D) an increase in heat energy leads to an increase in the kinetic energy leading to an increase in the temperature.

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The average radial velocity of galaxies in the Hercules cluster is 10,800 km/s. (a) using H0 = 73 km/s/Mpc, find the distance to

ArbitrLikvidat [17]

Answer:

a) 147.95 Mpc

Explanation:

Using Hubble's formula

$v = H_od$

where;

v = radical velocity

$H_o$ = Hubble's constant

d = distance

Given that:

The average radial velocity of galaxies in the Hercules cluster v = 10,800 km/s

Also using $H_o$ = 73 km/s/ Mpc ; we make distance d the subject of the formula:

Then distance d can be written as:

$d = \frac{v}{H_o}$

$d = \frac{10,800 \ km/s}{73 \ km/s/Mpc}$

d = 147.95 Mpc

Now, if the Hubble constant had a smaller value, then for a given velocity the distance to the galaxy will increase because distance d is inversely proportional to $H_o$

i.e

d ∝ $\frac{1}{H_0}$

4 0

3 years ago

Studies have shown that viewing violent actions in the media __________ the inhibition against performing those actions, especia

Airida [17]

Answer:

Decreases

Explanation:

4 0

3 years ago

Read 2 more answers

3. Given f(x) = x2 - 5x+3, then<br>A. f(-1) = -3<br>b. f(-1) = 7<br>f(-1) = -1<br>d. f(-1) = 9

Phantasy [73]

Answer:

$f(x) = {x}^{2} - 5x + 3 \\ f( - 1) = {( - 1)}^{2} - 5( - 1) + 3 \\ = 9$

7 0

3 years ago

Guys I need help with my homework please !!!!

Sergio [31]

Answer:

(a) To draw water from a well we have to pull at the rope.

(b) A charged body attracts an uncharged body towards it.

(d) The north pole of a magnet repels the north pole of another magnet.

Explanation:

Just trust me

6 0

3 years ago

15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea

Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0

4 years ago