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2 years ago

Which sections of the heating curve illustrate this process?

Physics

1 answer:

kirill115 [55]2 years ago

5 0

Answer:

B followed by D

Explanation:

The heat energy absorbed at B goes into potential energy that breaks the inter-molecular bonds and thus the constant temperature. Once the molecules have gained enough energy they escape the closely bonded structure and thus are free to move in random directions due to high kinetic energy. At this point (part D) an increase in heat energy leads to an increase in the kinetic energy leading to an increase in the temperature.

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A __________ is often written as an if/then statement. prediction law theory guess

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A hypothesis is often written as an if/then statement or prediction law theory guess. A hypothesis is also known as an educated guess.

Your answer is: Hypothesis

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3 years ago

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Answer:

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In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so

Pepsi [2]

Answer:

(a) 181.05 m/s²

(b) 13.2°

Explanation:

Given:

Radius of the circle (R) = 0.610 m

Angular acceleration (α) = 67.6 rad/s²

Angular speed (ω) = 17.0 rad/s

(a)

Radial acceleration of the ball is given as:

$a_r=\omega^2R$

Plug in the given values and solve for $a_r$ . This gives,

$a_r=(17.0\ rad/s)^2\times (0.610\ m)\\\\a_r=289\times 0.610\ m/s^2\\\\a_r=176.29\ m/s^2$

Now, tangential acceleration is given by the formula:

$a_t=R\alpha$

Plug in the given values and solve for $a_t$ . This gives,

$a_t=(0.610\ m)(67.6\ rad/s^2)\\\\a_t=41.236\ m/s^2$

Now, the magnitude of total acceleration is given as the square root of the sum of the squares of tangential and centripetal accelerations. Therefore,

$a_{Total}=\sqrt{(a_r)^2+(a_t)^2}$

Plug in the given values and solve for total acceleration, $a_{Total}$ . This gives,

$a_{Total}=\sqrt{(176.29)^2+(41.236)^2}\\\\a_{Total}=181.05\ m/s^2$

Therefore, the magnitude of total acceleration is 181.05 m/s².

(b)

Angle of total acceleration relative to radial direction is given by the formula:

$\theta=\tan^{-1}(\frac{a_t}{a_r})\\\\\theta=\tan^{-1}(\frac{41.236}{176.29})\\\\\theta=13.2\°$

Therefore, the total acceleration makes an angle of 13.2° relative to radial direction.

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3 years ago

Why neon is in the same group as helium?

guajiro [1.7K]

Neon and helium are both gases that fall under the Noble Gases section in the periodic table of elements.

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