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2 years ago

Which sections of the heating curve illustrate this process?

Physics

1 answer:

kirill115 [55]2 years ago

5 0

Answer:

B followed by D

Explanation:

The heat energy absorbed at B goes into potential energy that breaks the inter-molecular bonds and thus the constant temperature. Once the molecules have gained enough energy they escape the closely bonded structure and thus are free to move in random directions due to high kinetic energy. At this point (part D) an increase in heat energy leads to an increase in the kinetic energy leading to an increase in the temperature.

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Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of

Aleonysh [2.5K]

Answer:

r = 0.0548 m

Explanation:

Given that,

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.

We need to find the radius of their circular path. The formula for the radius of path is given by :

$r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}$

m is mass of Singly charged uranium-238 ion, $m=3.95\times 10^{-25}\ kg$

q is charge

So,

$r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m$

So, the radius of their circular path is equal to 0.0548 m.

4 0

2 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

3 0

2 years ago

Which statement is correct? (2 points)

Lemur [1.5K]

Answer:

When a neutral atom looses an electron to another neutral atom, two charged atoms are created.

Explanation:

On the off chance that one of the two unbiased particle looses an electron, it turns out to be emphatically (charge: +1), in light of the fact that the electron conveys a charge of - 1. Thus, the other atom which acknowledges the electron turns out to be adversely charged (charge: - 1). And in the end, we will have two charged atoms.

7 0

2 years ago

A metal sphere with a charge of +25 x 10-9 C is placed 2 m away from another metal sphere which carries a charge of +10 x 10^-9

serg [7]

Answer:

F = 5.625 10⁻⁷ N

Explanation:

For this exercise we use coulomb's law

F = $k \ \frac{q_1q_2}{r^2}$

where k is the Coulomb constant which is equal to 9 10⁺⁹ N m² /C²

as the charge on the two spheres has the same sign, the force is repulsive,

let's calculate

F = 9 10⁹ 25 10⁻⁹ 10 10⁻⁹ / 2²

F = 5.625 10⁻⁷ N

7 0

3 years ago

This is a model of a Neon atom. How likely is it that this atom would want to bond with another atom?

Kisachek [45]

Not very likely at all, because Neon already has 8 valance electrons in its outer shell

5 0

3 years ago