Answer:
Range will become 4 times of initial range
Explanation:
Let the velocity of projection is u
And angle at which projectile is projected is 
And acceleration due to gravity is 
So range of projectile is equal to 
........eqn 1
Now in second case it is given that velocity of launching is doubled
So new velocity 
So new range will be equal to 
.....eqn 2
Now dividing eqn 2 by eqn 1
So if we double the initial launch speed then range will become 4 times
The following are the answers to
the question presented:
<span>a. </span>magnitude of
the radial acceleration = 1.25m/s² inwardly directed
<span>b. </span>tangential
acceleration = 0.400m/s²
<span>c. </span>total
acceleration = 72.25 degrees
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
Force= mass times acceleration, so if the force is 18 and the acceleration is 3, the mass is 6. 18=(6)3.
Answer:
27 mph
Explanation:
9:45 to 11:45 = 2 hours
odometer says you traveled 54 miles in 2 hours or 27 mph
