Given:
In trapezoid
is the mid-segment of
.
To find:
The length of
.
Solution:
We know that the length of the mid-segment of a trapezoids is half of the sum of lengths of two parallel sides of the trapezoid.
In trapezoid
,




Isolate variable terms.


Now,




Therefore, the length of
is 230.
M = (20 - 12)/(4 - 2)
= 8/2
= 4
slope = m = 4
Answer:
given A=103° , B=24°
In triangle ABC,
A+B+C=180° [angle sum property of triangle]
103°+24°+C=180°
127°+C=180°
C=180°-127°
C=53°
hope it help u dear...
The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!
The Square Root of 245 is 15.65 (rounded to 2 dec. Places)