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Answer: Na2C2O4 probably sodium oxalate
Explanation: assume you have 100 g substance.
Mass of Na is m(Na) = 34.31 g, m(C) = 17.93 g and m(O) = 47.76 g.
Calculate moles n(Na) = 34.31 g/22.99 g/mol= 1.49 mol.
For C n(C) = 1.49 mol and n(O) = 2.985. You divide all by 1.49 you
Get n(Na) : n(C) : n(O) = 1:1:2 M(NaCO2) = 67 g/mol.
Divide 134:67 = 2. You get formula Na2C2O4
Answer:
474.64mmHg
Explanation:
From the question given, we obtained the following:
V1 = 10L
P1 = 655mmHg
V2 = 13.8L
P2 =?
P1V1 = P2V2
10 x 655 = P2 x 13.8
Divide both side by the coefficient P2 i.e 13.8
P2 = (10 x 655) / 13.8
P2 = 474.64mmHg
Therefore, the new pressure will be 474.64mmHg
<u> Increasing pH will </u><u>increase </u><u>solubility of the </u><u>PbI2</u>
What is equilibrium reaction ?
In a chemical reaction, chemical equilibrium is the state in which both the reactants and products are present in concentrations which have no further tendency to change with time, so that there is no observable change in the properties of the system.
PbI2 + 2OH- (aq) ----> Pb(OH)2(s) + 2I- (aq)
Pb(OH)2 is insoluble therefore increasing pH will lead to the formation of the more solid lead (ll)hydroxide which will help to solubulate more PbI2
therefore equilibrium will shift to right side means increasing pH will increase solubility of the PbI2.
Learn more about equilibrium reaction
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Answer:
11.72 grams
Explanation:
Let the equilibrium concentration of BrCl be y
Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M
Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M
From the equation of reaction
1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl
Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M
Kp = [BrCl]^2/[Br2][Cl2]
1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)
y^2/0.002356-0.0535y+0.25y^2 = 0.00011
y^2/0.00011 = 0.002356-0.0536y+0.25y^2
9090.9y^2-0.25y^2+0.0536y-0.002356 = 0
9090.65y^2+0.0535y-0.002356 = 0
The value of y must be positive and is obtained using the quadratic formula
y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M
Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams