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luda_lava [24]
3 years ago
10

Organisms that are most similar belong in a ,

Chemistry
1 answer:
solmaris [256]3 years ago
7 0

Answer:

The answer is D, organisms that are mostly related belong in a species.

Explanation:

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Evidence shows that interstellar bodies are moving far away from earth some faster than others which best suggest that the unive
igor_vitrenko [27]
The answer is B

Hope my answer was of assistance

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7 0
3 years ago
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How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M? 205 grams 0.205 grams 3.5
Firlakuza [10]
<span>A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.</span>
3 0
3 years ago
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When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample
andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

\Delta T = change in temperature = 1.643^oC

Now put all the given value in the above formula, we get:

26380J/g=0.235g\times c\times 1.643^oC

c=68323.38J/^oC

Thus, the specific heat of calorimeter is 68323.38J/^oC

Now we have to calculate the heat of combustion of caffeine.

Formula used :

Q=c\times \Delta T

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = 68323.38J/^oC

\Delta T = change in temperature = 1.584^oC

Now put all the given value in the above formula, we get:

Q=68323.38J/^oC\times 1.584^oC

Q=108224.23J=108.2kJ

Now we have to calculate the moles of caffeine.

\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

4 0
3 years ago
A purple rock as a mass of 316 grams and a density of 5.9 g/mL. Determine the volume of this rock in mL.
MakcuM [25]

Answer:

The answer is

<h2>53.56 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of rock = 316 g

density = 5.9 g/mL

The volume of the rock is

volume =  \frac{316}{5.9}  \\  = 53.5593220...

We have the final answer as

<h3>53.56 mL</h3>

Hope this helps you

5 0
3 years ago
URGENT PLEASE HELP!!
Orlov [11]

Answer:

Liters per second is 0.2 LPS

Liters per hour is 720

Explanation:

Divide the litres by the time, than multiply the time of an hour (in seconds) and than multiply the lps by time of an hour in seconds.

3 0
3 years ago
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