In one mole of talc, we observe that there are:
3 moles of Mg
4 moles of Si
2 moles of H
12 moles of O
The molar ratio of O to Mg is then:
12 moles of O : 3 moles of Mg = 4 : 1
Therefore, if 6.1 moles of Mg are present, the moles of O are:
4 * 6.1 = 24.4 moles of O
A amplitude = 0.50 m and wave-length = 1.0 m
B amplitude = 0.40 m and wave-length = 2.0 m
C amplitude = 0.60 m and wave-length = 2.0 m
Answer:
Molar mass = 1.111 × 10⁻⁵ g/mol
Explanation:
Given data:
Mass of polyethylene = 1.36 g
Volume = 100 mL (0.1 L )
Pressure = 1.86 torr (1.86/760 = 0.003 atm)
Temperature = 25 °C = 25 °C + 273.15 = 298.15 K
Molar mass of polyethylene = ?
Solution :
PV =nRT
n = PV/RT
n = 0.003 atm × 0.1 L / 0.0821 atm. L . mol⁻¹ .k⁻¹ × 298.15 k
n = 0.0003 atm. L / 24.5 atm. L . mol⁻¹
n = 1.2245 × 10⁻⁵ mol
Molar mass = mass / number of moles
Molar mass = 1.36g / 1.2245 × 10⁻⁵ mol
Molar mass = 1.111 × 10⁻⁵ g/mol
The Lewis structure of Chloroacetate (H₂CClCO₂) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with CH₂Cl and O⁻.
Formal Charge; Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Oxygen (Highlighted Red);Formal charge = 6 - [ 6 + 2/2]
Formal charge = 6 - [6 + 1]
Formal charge = 6 - [7]
Formal charge = -1