seen as an average successful rate of message delivery over a specific time period.
Answer:
19c
20d
21f
22e
23h
24a
25g
26b
Answer:
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 6.4 L of nitrogen monoxide gas
Explanation:
Equation of reaction: 4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)
From the equation of reaction, 5 moles of oxygen gas produces 4 moles of nitrogen monoxide gas
1 mole of a gas at STP occupies a volume of 22.4 L
5 moles of oxygen gas occupies a volume of 5 * 22.4 L = 112 L
4 moles of nitrogen monoxide as occupies a volume of 4 * 22.4 L = 89.6 L
Therefore, 89.6 L of nitrogen monoxide gas are produced from 112.0 L of oxygen
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 8.0 * (89.6/112
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 6.4 L of nitrogen monoxide gas
Elements that are found in potassium oxide is oxygen.