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3 years ago

In a certain Algebra 2 class of 30 students, 18 of them play basketball and 9 of them

Mathematics

1 answer:

marshall27 [118]3 years ago

3 0

Probability that a student will play both is 7/30

Step-by-step explanation:

Total students = 30

No. of students who play basketball = 18

Probability that a student will play basketball = 18/30

= 3/5

No. of students who play baseball = 9

Probability that a student will play baseball = 9/30

= 3/10

No. of students who play neither sport = 10

Probability that a student will play neither sport = 10/30

= 1/3

To find :

Probability that a student will play both = p(student will play both)

No.of students who play sport = 30 - 10

= 20

Out of 20 students 18 play basketball and 9 play baseball.

So, some students play both the sports.

No. of students who play both sports = 18 + 9 - 20

= 7

p(student will play both) = 7/30

Probability that a student will play both is 7/30

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

a week before election day, 276 out of 450 people said they would vote for the republican candidate. if 15,240 registered voters

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Answer:

(a) $\frac {276}{450}=\frac {y}{15240}$

(b) We cross multiply the probability by the total voters

Step-by-step explanation:

(a)

Probability of getting a republican voter is

$\frac {276}{450}=\frac {138}{225}=\frac {46}{75}$

$\frac {276}{450}=\frac {138}{225}=\frac {46}{75}=\frac {y}{15240}$

These are found by dividing the first numerator and denominator by 2, then by 3

To make it complete, the situation is therefore defined as $\frac {276}{450}=\frac {y}{15240}$ where y is unknown value

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Cross multiplication of the probability and number of voters gives the actual figure of y in the equation formed in part a of the question.

(c)

Since we have 15240 voters who plan to participate in election, we cross multiply to get the approximate number of republican voters which yields

$\frac {46}{75}\times 15240=9347.2\approx 9347$

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