Answer:
Are you missing part of question or maybe options
Answer:
C.
Step-by-step explanation:
The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then
∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that
= x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
A = {0, 1, 2, 3}
C = {0, a, 2, b}
A ∩ C = {0, 2} → E)
A set of the same elements from the set A and the set C.