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Anton [14]
3 years ago
11

How many moles are in 2.31*10^21 atoms of lead

Chemistry
1 answer:
Anon25 [30]3 years ago
6 0
Hey there!:

Molar mass Lead  ( Pb ) = 207.2 g/mol

Therefore:

1 mole Pb --------------------- 6.02*10²³ atoms
? moles Pb -------------------- 2.31*10²¹ atoms

moles Pb = ( 2.31*10²¹ ) * 1 / ( 6.02*10²³ ) = 

moles Pb = ( 2.31*10²¹ ) / ( 6.02*10²³ ) = 

=> 0.00383 moles of Pb

Hope this helps ! 
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Strongly acidic [or strongly basic] solution will have high conductivity.

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Answer:

Explanation:

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This relationship is defined by Charles' law

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What this means is that as long as the pressure remains unchanged, when the volume increases, the temperature increases, and when the volume decreases, the temperature decreases

These can be represented by the mathematical formula below:

\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}

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1 year ago
Phenolphthalein has a pKa of 9.7 and is colorless in its acid form and pink in its basic form. calculate [In-}/{HIn} for the fol
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Answer:

1.58x10⁻⁵

2.51x10⁻⁸

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pH = pKa + log[In-]/[HIn]

pKa = -logKa, and Ka is the equilibrium constant of the dissociation of the acid. [X] is the concentrantion of X. Thus,

i) pH = 4.9

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log[In-]/[HIn] = - 4.8

[In-]/[HIn] = 10^{-4.8}

[In-]/[HIn] = 1.58x10⁻⁵

ii) pH = 2.1

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log[In-]/[HIn] = -7.6

[In-]/[HIn] = 10^{-7.6}

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iii) pH = 7.8

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[In-]/[HIn] = 0.0126

iv) pH = 11.5

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log[In-]/[HIn] = 1.8

[In-]/[HIn] = 10^{1.8}

[In-]/[HIn] = 63.10

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3 years ago
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