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2 years ago

Characteristics used to describe matter are called

Chemistry

1 answer:

Shtirlitz [24]2 years ago

5 0

Answer:

A.physical properties

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It goes away

Explanation:

cause the IR light only can see through clean glass.

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2 years ago

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What is observed when an iron bar is

bija089 [108]

Answer:
b). of copper (II) sulfate

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3 years ago

Given the following formula for calculating the ionization energy of one-electron species such as Li2+, He+, and H, calculate th

Yuki888 [10]

Answer:

The answer is " $32819.9 \ \frac{J}{mol}\\\\$ "

Explanation:

$Boron: 5^{B}\to 1s^2 2s^2 2p^1$

$\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\$

$=-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\$

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2 years ago

The ability of a material to burn (its flammability) is an indication of the materials reactivity with oxygen. Does the informat

Nataliya [291]

Answer:

Yes, this theory supports the inert nature of noble gases.

Explanation:

Noble gases already attain octet state stability, by having their outer shells completely filled with electrons. This makes them unable to take part in chemical reaction (by lose, gain or sharing of electrons).

Flammability occurs when matter burns through combination with oxygen, and changes to a different substance.

I hope this explanation is clear, let me know if I can be of further assistance.

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2 years ago

I've seen some people having trouble on this question and now I am also stuck on this. I've tried my best to answer but I don't

prisoha [69]

Answer:

approximately 1.772 grams

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

$3 \times \frac{132}{78} = 1.772 \: g \: al(oh)3$

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2 years ago