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3 years ago

PLEASE HELP TEST density question EASY

Chemistry

2 answers:

AlexFokin [52]3 years ago

7 0

it will float because it is not heavy enough

valentinak56 [21]3 years ago

5 0

Answer:

float

Explanation:

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Material use make car tyres and chewing gum?

Ulleksa [173]

Answer:

Rubber

Make me brainlyist

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3 years ago

You are a chemist working in your laboratory. In your storage closet you have a

Nastasia [14]

Ans is B.Bromine. Only two elements are liquid at room temperature ( mercury and Bromine) . Helium and chlorine, arsenic are gases.

8 0

3 years ago

Solid carbon is known to react with oxygen gas to produce carbon dioxide. If a mass of 1.2g of carbon is burned in oxygen, 4.4g

Elden [556K]

Now ,

C + O2 → CO2

According to above equation, 1 mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.Thus this implies that 12 g of carbon reacts with 32 g of O2 to produce 44 g of CO2.

No of moles = mass of the substance/molecular mass of the substance.

In this case 1.2 g of carbon reacts with "x "g of O2 to produce 4.4 g of CO2.

No of moles of carbon in this case = 1.2÷ 12 = 0.1 moles.

No of moles of carbon dioxide formed = 4.4÷44 =0.1 moles

Thus already discussed above, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. Hence to produce 0.1 mole of CO2 ,0.1 mole of carbon needs to react with 0.1 mole of oxygen.

Also number of moles of O2 = mass of O2÷ molar mass of O2

Substituting number of moles of O2 as 0.1 we get

mass of O2(x) = Number of moles of O2 × Molar mass of O2

Mass of O2 (x) = 0.1 × 32= 3.2 g

Thus mass of 3.2 g O2 reacts with 1.2 g of CO2 to produce 4.4 g of CO2.

7 0

3 years ago

A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio

____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

The units are mole fraction, molality and mass%

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = 59,0 moles of water

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = 0,0157

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = 0,889m

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = 16%

I hope it helps!

6 0

3 years ago

Aluminum flouride+ sulfuric acid=

Alexxx [7]

you get hydrofluoric acid

6 0

3 years ago