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3 years ago

PLEASE HELP TEST density question EASY

Chemistry

2 answers:

AlexFokin [52]3 years ago

7 0

it will float because it is not heavy enough

valentinak56 [21]3 years ago

5 0

Answer:

float

Explanation:

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Consider these ground-state ionization energies of oneelectron species:

SVETLANKA909090 [29]

Answer:

Explanation:

general expression for the ionization energy of any one-electron species.

= z² x ground level energy / n²

z is atomic no , n is energy level .

ground level energy of

H = 1.31 x 10³ kJ/mol

He⁺ = 2² x 1.31 x 10³ kJ/mol = 5.24 x 10³ kJ/mol

Li²⁺ = 3² x 1.31 x 10³ kJ/mol = 1.18 x 10⁴ kJ/mol

b ) the ionization energy of B⁴⁺.

= 5² x 1.31 x 10³ kJ/mol = 32.75 x 10³ kJ/mol

c ) minimum energy required to remove the electron from the n = 3 level of He⁺ per mole

= 5.24 x 10³ / 9 kJ/mol

= 5.82 x 10² kJ/mol

= 5.82 x 10² x 10³ / 6.02 x 10²³ J

.9667 X 10⁻¹⁸ J

= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV

= 6.042 eV

= 1237.5 / 6.042

= 204.82 nm

d )

3 0

3 years ago

A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

4 0

3 years ago

How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and

Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

$(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)$

The expression used will be:

$Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]$

where,

$Q$ = heat released for the reaction = ?

m = mass of benzene = 94.4 g

$c_{p,s}$ = specific heat of solid benzene = $1.51J/g^oC=1.51J/g.K$

$c_{p,l}$ = specific heat of liquid benzene = $1.73J/g^oC=1.73J/g.K$

$\Delta H_{fusion}$ = enthalpy change for fusion = $-9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g$

Now put all the given values in the above expression, we get:

$Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]$

$Q=-29427.312J=-29.4kJ$

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0

3 years ago

Does a bag of soil weigh kilograms or grams

Airida [17]

A bag of soil will weigh in kilograms

7 0

3 years ago

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What is one substance that is 100x more acidic than baking soda

daser333 [38]

Answer:

An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution. This kind of solution is acidic.

Explanation:

8 0

3 years ago