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2 years ago

PbSO4, Spell out the full name of the compound.

Chemistry

1 answer:

andreyandreev [35.5K]2 years ago

4 0

Answer:

Lead (II) Sulfate

Explanation:

Don't forget to add the (II) marking indicating that lead has a charge of 2+ (because Sulfate has a charge of 2-, balancing the ion).

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What carries electric current from the cell to the other components of a circuit.

Rasek [7]

Answer:

The different objects that make up a circuit are called components. A circuit must have a power source, such as a battery, and the current flows through a conductor, such as a wire.

Explanation:

I hope that was useful.

3 0

2 years ago

Please help , science tho. by the way i have to do 5

kap26 [50]

Answer:

850

Explanation:

It's between 840 and 860

8 0

2 years ago

For the reaction N2(g) + 2H2(g) → N2H4(l), if the percent yield for this reaction is 100.0%, what is the actual mass of hydrazin

barxatty [35]

Answer:

53.6 g of N₂H₄

Explanation:

The begining is in the reaction:

N₂(g) + 2H₂(g) → N₂H₄(l)

We determine the moles of each reactant:

59.20 g / 28.01 g/mol = 2.11 moles of nitrogen

6.750 g / 2.016 g/mol = 3.35 moles of H₂

1 mol of N₂ react to 2 moles of H₂

Our 2.11 moles of N₂ may react to (2.11 . 2) /1 = 4.22 moles of H₂, but we only have 3.35 moles. The hydrogen is the limiting reactant.

2 moles of H₂ produce at 100 % yield, 1 mol of hydrazine

Then, 3.35 moles, may produce (3.35 . 1)/2 = 1.67 moles of N₂H₄

Let's convert the moles to mass:

1.67 mol . 32.05 g/mol = 53.6 g

4 0

3 years ago

...............………...mkmlkml;m

bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

$x = 2925 \div 0.5 \times 15 = 390$

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0

2 years ago

Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?

TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

$2Al+6HBr\rightarrow 2AlBr_3+3H_2$

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

$8molAl(\frac{6molHBr}{2molAl})$

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

7 0

2 years ago

PbSO4, Spell out the full name of the compound.​

PbSO4, Spell out the full name of the compound.