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Aloiza [94]
4 years ago
11

What is the range of the relation?

Mathematics
1 answer:
Bas_tet [7]4 years ago
7 0
They are on quarenent one
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What is 43434 x 21387128930523122222 and the first person to answer will get a brainliest from me!!!!!!!!!!!!!1
Solnce55 [7]

Answer:

9.2892856e+23

Step-by-step explanation:

have a good day!

3 0
3 years ago
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How many are 3 raised to 2 ???​
Anettt [7]

Answer:

\huge \boxed{9}

Step-by-step explanation:

3 raised to 2 is 3 to the power of 2.

3^2 =3 \times 3 = 9

3 is multiplied by itself.

7 0
4 years ago
Need help with b, c and d for 15 points
stich3 [128]
B is miles he went, for c at the rate he's going at he'll probably be there after five minutes that is all I know 
4 0
3 years ago
Suppose that 80 percent of all statisticians are shy, whereas only 15 percent of all economists are shy. Suppose also that 90 pe
Anna71 [15]

Answer:

37.21% probability that the person is a statistician.

Step-by-step explanation:

We have these following probabilities:

An 80% probability that a statistican is shy.

A 15% probability that an economist is shy.

At the gathering, a 90% probability that a person is an economist.

At the gathering, a 10% probability that a person is a statistican.

If you meet a shy person at random at the gathering. What is the probability that the person is a statistician?

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the person is a statistican, given that he is shy?

P(B) is the probability of the person being a statistican. So P(B) = 0.1.

P(A/B) is the probability of a statistican being shy, so P(A/B) = 0.8.

P(A) is the probability of a person being a shy. This is 15% of 90%(economists) and 80% of 10%(statisticans). So

P(A) = 0.15*0.9 + 0.8*0.1 = 0.215

Finally

P = \frac{P(B).P(A/B)}{P(A)}

P = \frac{0.1*0.8}{0.215} = 0.3721

37.21% probability that the person is a statistician.

3 0
3 years ago
I NEED HELP PLEASE ASAP! :)
Nonamiya [84]

Answer:

( About ) 1,099 pounds

Step-by-step explanation:

The force required to keep this truck from rolling down the hill is opposed by the force of friction, comparative to the 2600 pounds of force against this friction. It should be that this opposing force is at work more towards the bottom of this hill, and thus the question asks the magnitude of latter force to keep this truck idle -

|| F || = sin( 25 ) * ( Fg ) = sin( 25 ) * ( 2600 lb ) = ( About ) 1098.80748 pounds

<u><em>This can be rounded to a solution of 1099 pounds</em></u>

7 0
3 years ago
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