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chubhunter [2.5K]
3 years ago
9

Find the simple interest on 7,200 at 3/4% for 5 years​

Mathematics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

$7474.08

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Simple Interest Rate Formula: \displaystyle A = P(1 + r)^t

  • A is final amount
  • P is principle (initial) amount
  • r is rate
  • t is time (in years)

Step-by-step explanation:

<u>Step 1: Define</u>

P = 7200

r = 0.75% = 0.0075

t = 5

<u>Step 2: Solve for </u><em><u>A</u></em>

  1. Substitute in variables [Simple Interest Rate Formula]:                               \displaystyle A = 7200(1 + 0.0075)^5
  2. (Parenthesis) Add:                                                                                          \displaystyle A = 7200(1.0075)^5
  3. Evaluate exponents:                                                                                       \displaystyle A = 7200(1.03807)
  4. Multiply:                                                                                                           \displaystyle A = 7474.08
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Step-by-step explanation:

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7 0
3 years ago
1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t
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Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, N_{0}   = 7652 in 2016.

a) Exponential growth model is given by N(t) = N_{0} e^{kt} where t is the time in years after 2016.

 Year 2016 is when t = 0.

  k = growth rate constant = 1.6% = 0.016

 i) therefore the population of the town in 2024

    = N = N_{0} e^{kt}  = 7652e^{0.016\times8}  = 8697   ( to the nearest whole number)

2.) log (I \times M \times S) = magnitude of earthquake  where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore  I \times M \times S = 10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}

therefore \frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2}  = \frac{10^{8} }{10^{6} }  = 100

 

3 0
3 years ago
PLEASE HELP ME <br><br> i’ll mark brainliest if you’re correct
AlladinOne [14]

Answer:

13

Step-by-step explanation:

Write an equation setting the lengths equal to each other.

5x + 3 = 2x + 9

Move the variable (x) to one side. I'm going to subtract 2x from both sides.

5x - 2x + 3 = 2x - 2x + 9

3x + 3 = 9

Subtract 3 from both sides

3x +3 - 3 = 9 - 3

3x = 6

Divide both sides by 3

3x/3 = 6/3

x = 2

Now use 2x + 9 to find the length of EG by substituting 2 in for x.

2x + 9

2(2) + 9

4 + 9

13

You could also use 5x + 3 to find the length of EG by substituting 2 in for x.

5 0
2 years ago
Read 2 more answers
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