Answer:
Explanation:
The figure is not provided and we don't know the force applied to the books.
Therefore, here we are going to assume the force applied is 3 N:
F = 3 N
We can find the acceleration of the stack of books by using Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:
where
F is the force
m is the mass
a is the acceleration
In this problem we have
m = 1.5 kg is the mass of the books
Therefore, the acceleration is:
1,000 milligrams = 1 gram
2,000 milligrams = 2 grams
3,000 milligrams = 3 grams
4,000 milligrams = 4 grams
Answer:
Explanation:
If a number of less than 1, then the number has a decimal point like
0.085, 0.008 e.t.c.
The zeros before the none zero digit are insignificant. The significant figure is 8 and 5.
But if there a zero between the none zero e.g. 0.0087056
Here the zero between 7 and 5 is significant, then the significant numbers are 8,7,0,5,6
But if the zero is not in between the none zero digit, then the zero is insignificant
E.g 0.05800
The last two zero is insignificant, the significant number is 5 and 8
So, If a positive numbers less than 1, the zeros between the decimal point and a non-zero number are NOT significant.
Answer:
2×10⁻⁷ Ωm
Explanation:
From the question,
R = 4ρL/πd².................... Equation 1
Where R = Resistance of the wire, ρ = resistivity of the wire, L = length of the wire, d = diameter of the wire.
Therefore,
ρ = Rπd²/4L............. Equation 2
Given: R = 1 ohm, ρ = 1×10⁻⁷Ωm
1×10⁻⁷ = πd²/4L.................... Equation 3
If the length and the diameter are doubled, and the resistance remaining constant
ρ' = π(2d)²/4(2L)
Where ρ' = new resistivity
ρ' = 4πd²/8L
ρ' = 2πd²/4L = 2ρ
ρ' = 2(1×10⁻⁷)
ρ' = 2×10⁻⁷ Ωm
Average speed is the ratio of total distance moved by Chi in total time interval
So here we will have
Total distance = 100 m + 400 m
Total time taken = 5 min + 15 min = 20 min
now by the formula of average speed we know that
so average speed will be 1.5 km/h