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1 year ago

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An object is moving in a straight line with a constant acceleration. Its position is measured at three different times, as shown

in the table below.
Time (s) 1 Position, (m)
37.70 9.600
39.30 18.048
40.90 33.792
Calculate the magnitude of the acceleration at t=39.30

1 answer:

stiv31 [10]1 year ago

4 0

The constant acceleration of the object is $0.414\ m/s^2$ .

<h3>Acceleration of the object</h3>

The acceleration of the object is constant, and the values at the three different positions is the same.

<h3> For the first position and time</h3>

$s = v_0 t + \frac{1}{2} at^2\\\\37.7 = v_o(9.6) +\frac{1}{2} a(9.6)^2\\\\ 37.7 = 9.6v_0 + 46.08a$

<h3>For the second position and time</h3>

$39.3 = v_o(18.048) +\frac{1}{2} a(18.048)^2\\\\ 39.3 = 18.048v_0 + 162.87a$

<h3>Solve the first and second equation together</h3>

$37.7 = 9.6v_0 + 46.08a\\\\39.3 = 18.048v_0 + 162.87a\\\\18.048: \ \ 680.41 = 173.261v_0 + 831.651a\\\\9.6: \ \ \ \ -(377.28 = 173.261 v_0+ 1563.552a)\\------------------\\303.13 = -731.901a\\\\-a = \frac{303.13}{731.901} \\\\-a = 0.414 \ m/s^2\\\\|a| = 0.414 \ m/s^2$

Thus, the constant acceleration of the object is $0.414\ m/s^2$ .

Learn more about acceleration here: brainly.com/question/14344386

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Answer:

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Explanation:

Velocity can be found using the following formula:

$v=\frac{p}{m}$

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The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

$p= 200 \ kgm/s\\m=55 \ kg$

Substitute the values into the formula.

$v=\frac{200 \ kg m/s}{55 \ kg}$

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(a) Proton, (b) Electron (c) tau neutrino.

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The charge of a single electron is $q=1.6 \cdot 10^{-19} C$ , so the number of electrons flown through the hair dryer is the total charge divided by the charge of a single electron:
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The initial velocity of car 1 is 20 m/s to the right

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$u_2 = 0$ is the initial velocity of the second car

$v_2$ is the final velocity of the second car

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And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

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