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STatiana [176]
3 years ago
12

Which expanded expressions represent the exponential expression (–4)3 · p4? Select all that apply. (–4) · (–4) · (–4) · (–4) · p

· p · p p · p · p · p · (–4) · (–4) · (–4) p · (–4) · (–4) · p · (–4) · p p · p · (–4) · (–4) · p · p · (–4) (–4) · p · p · p · (–4) · (–4) · (–4) (–4) · (–4) · p · (–4) · p · p · p
Mathematics
2 answers:
Alexxx [7]3 years ago
4 0

Answer:

(-4)(-4)(-4)(p)(p)(p)(p)

Step-by-step explanation:

= (-4)^3 * p^4

The expanded form of it is:

= (-4)(-4)(-4)(p)(p)(p)(p)

Kamila [148]3 years ago
3 0
<h2>Answer: <u><em>B,D,F!! These are the correct answers!!!</em></u></h2>

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What is the reciprocal of 6/9​
neonofarm [45]

Answer:

<h2>9/6</h2>

Step-by-step explanation:

Remember that, to find the reciprocal of a fraction, just swap the numbers. So the reciprocal of 6/9 is 9/6.

3 0
3 years ago
Read 2 more answers
Alex takes a multiple-choice quiz in his Anthropology 100 class. The quiz has 10 questions, each has 4 possible answers, only on
Andreas93 [3]

Answer:

The probability is 0.28157

Step-by-step explanation:

The number of answers are 40 answers ( 10 questions and 4 answer each)

The number of correct answers is only 10

So the probability that he answers 2 exactly out of 10 means he correctly selected 2 answers

The probability will be;

10 C 2/ 40 C 10

This mean out of the total 10 correct, he selects 2 and out of the total 40 , he selects 10

The probability of selecting a correct answer is;

1/4 while the probability of selecting a wrong one is 3/4

So probability of selecting 2 correct out of a total 10 will be

10 C 2 (1/4)^2 (3/4)^8

= 0.28157

4 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
I need help with this problem plzzz
Effectus [21]

Not sure sorry but you can. Try searching on google or yahoo answers

6 0
3 years ago
70 hundred is equal to how many thousands
Ann [662]
70 x 100 = 7,000

Therefore, 70 hundred is equal to 7 thousands.
8 0
3 years ago
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