Please help
In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.
2 answers:
Answer:
The dimension of A is 38.17
Step-by-step explanation:
Using the sine law
a/sin A = b/ sin B
For the question In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.
a/sin A = b/ sin B
Sin A = 82
b = 27
Sin B = 58
a/ 82 = 27/58
58a = 27 ×82= 2214
a = 2214/58 = 38.1724= 38.17
Answer:
31.5
Step-by-step explanation:
a/sinA = b/sinB
a/sin(82) = 27/sin(58)
a = 31.52797345
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