Question

Please help In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.

Answer 1

Answer:

The dimension of A is 38.17

Step-by-step explanation:

Using the sine law

a/sin A = b/ sin B

For the question In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.

a/sin A = b/ sin B

Sin A = 82

b = 27

Sin B = 58

a/ 82 = 27/58

58a = 27 ×82= 2214

a = 2214/58 = 38.1724= 38.17

Answer 2

Answer:

31.5

Step-by-step explanation:

a/sinA = b/sinB

a/sin(82) = 27/sin(58)

a = 31.52797345