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erastovalidia [21]
4 years ago
7

A 0.157 kg ball is thrown straight up from 2.33 m above the ground. Its initial vertical speed is 11.60 m/s. A short time later,

it hits the ground. Calculate the total work done by the force of gravity during that time.
Physics
1 answer:
klasskru [66]4 years ago
6 0

Answer:

14.148 J

Explanation:

Work : This can be defined as the product of force and the distance moved along the direction of force. The S.I unit of work is Joules.(J).

From the question,

The Total work done by the field = Kinetic energy of the ball + Potential energy of the ball

Wt = 1/2mv²+mgh......................... Equation 1

Where Wt = Total work done by the ball, m = mass of the ball, v = velocity of the ball, g = acceleration due to gravity of the ball, h = height of the ball.

Given: m = 0.157 kg, v = 11.60 m/s, h = 2.33 m, g = 9.8 m/s²

Substitute these values into equation 1

Wt = 1/2(0.157)(11.6²) + (0.157)(2.33)(9.8)

Wt = 10.563+3.585

Wt = 14.148 J

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A lumberjack is chopping wood with an ax. How does the ax make the lumberjack's job easier? A. The ax is heavy so it can split w
zhenek [66]

Answer: B

Explanation:

A machine multiplies the work output of a something by some amount. In this question, the ax is the machine. Thus, the ax is multiplying the work outputted by the lumberjack, so the answer is B. The reason it is not C is because there could be other forces interacting on the wood which the ax can affect.

5 0
3 years ago
Mr. White claims that he invented a heat engine with a maximum efficiency of 90%. He measured the temperature of the hot reservo
Studentka2010 [4]

Answer:

The error he made was that he didn't convert the unit of temperature to Kelvin.

The correct efficiency is 24%

Explanation:

Parameters given:

Temperature of hot reservoir = 100°C = 373 K

Temperature of cold reservoir = 10°C = 273 K

The efficiency of a heat engine is given as:

E = 1 - (Qc/Qh) = 1 - (Tc/Th)

Where

Qc = Output heat;

Qh = Input heat;

Tc = Temperature of the cold reservoir;

Th = Temperature of the hot reservoir.

=> E = 1 - (283/373)

E = 1 - 0.76

E = 0.24

In percentage,

E = 0.24 * 100 = 24%

Hence, the efficiency of the engine is actually 24%.

The error he made was that he didn't convert the temperature to Kelvin. If we leave the temperatures in °C, we have that:

E = 1 - (10/100)

E = 1 - 0.1 = 0.9

In percentage,

E = 0.9 * 100 = 90%

7 0
3 years ago
The speed of all electromagnetic waves is 3.00 × 108 meters per second. What is the wavelength of an X-ray with a frequency of 1
Ierofanga [76]
The answer is......2.54x10^-10......
8 0
4 years ago
Read 2 more answers
Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second
vampirchik [111]

To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.

From the law of Malus intensity can be defined as

I' = \frac{I_0}{2} cos^2 \theta

Where

\theta =Angle From vertical of the axis of the polarizing filter

I_0 = Intensity of the unpolarized light

The expression for the intensity of the light after passing through the first filter is given by

I = \frac{I_0}{2}

Replacing we have that

I = \frac{370}{2}

I = 185W/m^2

Re-arrange the equation,

I'= \frac{I_0}{2}cos^2\theta

Re-arrange to find \theta

cos^2\theta = \frac{2I'}{I_0}

cos^2\theta = \frac{2*138}{370}

\theta = cos^{-1}(\sqrt{\frac{2*138}{370}})

\theta = 0.5282rad

\theta = 30.27\°

The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Varvara68 [4.7K]

The answer to your question is,

4 kilometers north

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