Answer:
The second ball moves with 0.83 m/s forward.
Explanation:
Given;
mass of the first ball, m₁ = 3 kg
initial velocity of the first ball, u₁ = 5 m/s
final velocity of the first ball, v₁ = 2.5 m/s
mass of the second ball, m₂ = 9kg
initial velocity of the second ball, u₂ = 0
final velocity of the second ball, v₂ = ?
From the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(3x5) + (9x0) = (3x2.5) + (9v₂)
15 = 7.5 + 9v₂
15 - 7.5 = 9v₂
9v₂ = 7.5
v₂ = 7.5/9
v₂ = 0.83 m/s
The second ball moves with 0.83 m/s forward.
