Answer:
Explanation:
a ) Between r = 0 and r = r₁
Electric field will be zero . It is so because no charge lies in between r = 0 and r = r₁ .
b ) From r = r₁ to r = r₂
At distance r , charge contained in the sphere of radius r
volume charge density x 4/3 π r³
q = Q x r³ / R³
Applying Gauss's law
4πr² E = q / ε₀
4πr² E = Q x r³ / ε₀R³
E= Q x r / (4πε₀R³)
E ∝ r .
c )
Outside of r = r₂
charge contained in the sphere of radius r = Q
Applying Gauss's law
4πr² E = q / ε₀
4πr² E = Q / ε₀
E = Q / 4πε₀r²
E ∝ 1 / r² .
#16
If we put a resistor in circuit it will slow the speed of current
Let's check ohms law
- So if resistance is more current is less
#17
Again use ohms law
- Voltage must be increased
Answer:
Both of them.
Explanation:
They are both because when your analyzing data , that is what happen's.
The answer is the vehicle. At the precise moment of the impact in a collision, there is the release of energy when a vehicle strikes another vehicle or another object. Earlier to an impact, a vehicle and everything inside the vehicle is traveling at whatever speed the vehicle had been going. As the collision continues, the vehicle slowly loses energy. However, the vehicle occupants and any others items in the vehicle continue to move forward at the same speed as the vehicle had been traveling prior to impact.
