A car travels 30 km north in 25 min. and 40 km east in 35 min. What is the total time in hours? Be careful to carry over

Sloan [31]

An earthworm moves by using two different sets of muscles. 2. FISHES :- Fish swim by flexing their bodies and tail back and forth. Fish stretch or expand their muscles on one side of their body, while relaxing the muscles on the other side.

3 0

3 years ago

A uniform beam is suspended horizontally by two identical vertical springs that are attached between the ceiling and each end of

puteri [66]

The frequency and amplitude of the SHM beam is 0.8 Hz and 0.098 m. The frequency of the SHM wave when gravel falls is 0.8 Hz and the amplitude of subsequent SHM beam is 0.4m.

(a) Mass of the spring = 225 Kg

Mass of the sack = 175 Kg

Amplitude of the beam = 40 cm = 0.40 m

Frequency of the beam = F = 0.60 cycles/s

The formula for frequency of oscillation =

= f = (1/2π) X √(k/m)

where, k = 2π²F²m

= k = 2 X (3.14)² X 0.6² X (225 + 175)

= k = 5685.37 N/m

Strength of the spring before gravels fall = x =

= x = mg / k

= x = [ (225 + 175 ) X 9.8 ] / 5685.37

= x = 0.689 m

But, the spring is stretched by the distance of x' which is expressed as,

= X = x - x'

= X = 0.689 - 0.40

= X = 0.289 m

Now, since we know that the gravel falls, thus frequency = f =

= f = (1/2π) X √(k/m)

= f= (1/ 2 X 3.14) X √ 5685.37 / 225

= f = 0.8 Hz

(b) Assuming that the spring is stretched, x = mg/k =

= x = (225 X 9.8) / 5685.37

= x = 0.3878 m

Thus, the amplitude of the sack = A = 0.3878 - 0.289

= A = 0.098 m

(c) If the gravel falls, the speed is maximum hence speed = s =

= s = A X √(k/m)

= s = 0.4 X √(5685.37/400)

= s = 1.508 m/s

The frequency = f' =

= f' = (1/2π) X √(k/m)

= f' = (1/2 X 2.14) X √(5685.37/225)

= f' = 0.8 Hz

(d) New amplitude = A' =

= A' = 0.38 + 0.038 (after calculating the new distance)

= A' = 0.4 m

To know more about Spring:

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8 0

2 years ago

If 63 joules of work were necessary to move a 3.50 newton crate, how far was the crate moved?

katovenus [111]

Divide them by 53 and 3.50

5 0

3 years ago

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If a = 2.0 cm, b = 5.0 cm, and i = 20 a, what is the magnitude of the magnetic field at the point p?

attashe74 [19]

If a = 2.0 cm, b = 5.0 cm, and i = 20 a, 6.0 μt is the magnitude of the magnetic field at the point p, So the correct option is (a).

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

$B_{1}$ = μ $_{0}$ i $\frac{\pi }{6}$ / $4\pi (a+b)$