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Evgen [1.6K]
3 years ago
12

|5 + z| + 3 = 10 solve

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

z = 2

Step-by-step explanation:

The | | represents absolute value which means the number's distance from 0. Any number's absolute value is going to be a positive number.

So, 5 + what number plus 3 gives you 10?

10 - 3 = 7 and 7 - 5 = 2.

So, |5 + 2| + 3 = 10.

The distance from 5 and 0 is 5

Distance from 2 and 0 is 2

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Can somebody explain Scatter Plots and Equations of Lines for me. I'm not quite understanding it
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3 years ago
Are 6(3x+1) and 9X +6+ 9X Equivalent
Dominik [7]

Answer:

yes, it is equivalent!!

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3 0
3 years ago
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Ganezh [65]

Answer : option A

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Inter quartile range is the middle 50% of the given range of scores.

The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%

From the diagram , we can see that

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8 0
3 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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