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sladkih [1.3K]
3 years ago
6

Write the all factors and find the GCF for 4,10,12,16 thank you

Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

The GFC is 2

Step-by-step explanation:

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7 0
3 years ago
(4,-1). Parallel to y=-4x+2
allochka39001 [22]

Answer: x=1/2

Step-by-step explanation:

y= - 4x + 2

X=1/2

6 0
3 years ago
The area of a square mat is 125 square inches. The best approximation of its length is inches. If the length of each side is inc
gtnhenbr [62]
The area of a square is simply the side length squared and we are given that the area is 125 so:

s^2=125

s=√125

s=5√5

Now using the area equation again, and adding 1 inch to s we have:

A=(s+1)^2, and using s found above we have:

A=(5√5+1)^2

A=125+10√5+1

A=126+10√5 in^2

A≈148.36 in^2  (to nearest hundredth of a square inch)
4 0
3 years ago
Read 2 more answers
What gives the range of the function y=|x-1|+7
riadik2000 [5.3K]
The rage of the function is x=-6
6 0
3 years ago
Help -------------------------
34kurt

Answer:

(A) -3 ≤ x ≤ 1

Step-by-step explanation:

The given function is presented as follows;

h(x) = x² - 1

From the given function, the coefficient of the quadratic term is positive, and therefore, the function is U shaped and has a minimum value, with the slope on the interval to the left of <em>h</em> having a negative rate of change;

The minimum value of h(x) is found as follows;

At the minimum of h(x), h'(x) = d(h(x)/dx = d(x² - 1)/dx = 2·x = 0

∴ x = 0/2 = 0 at the minimum

Therefore, the function is symmetrical about the point where x = 0

The average rate of change over an interval is given by the change in 'y' and x-values over the end-point in the interval, which is the slope of a straight line drawn between the points

The average rate of change will be negative where the y-value of the left boundary of the interval is higher than the y-value of the right boundary of the interval, such that the line formed by joining the endpoints of the interval slope downwards from left to right

The distance from the x-value of left boundary of the interval that would have a negative slope from x = 0 will be more than the distance of the x-value of the right boundary of the interval

Therefore, the interval over which <em>h</em> has a negative rate of change is -3 ≤ x ≤ 1

8 0
3 years ago
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