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enyata [817]
3 years ago
7

Which of these statements about mixtures is true?

Chemistry
2 answers:
Lerok [7]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

When two or more different substances are mixed together then it results in the formation of a mixture.

Mixture are of two types, that is, homogeneous mixture and heterogeneous mixture.

In homogeneous mixture, the constituent particles are distributed evenly throughout the mixture.

Whereas in heterogeneous mixture, the constituent particles are non-uniformly distributed.

Thus, we can conclude that mixtures are classified based on the distribution of particles in them.

Karo-lina-s [1.5K]3 years ago
3 0
The best answer from the choices would be the last option. <span>Mixtures are classified based on the distribution of particles in them. The classification are called homogeneous and heterogeneous mixtures. The former type describes a mixture where all components are distributed evenly. The latter type is a mixture where the components do not have uniformity in the mixture.</span>
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Which of the following regarding atmospheric pressure is true?
butalik [34]

Answer:

1- Option (A)

2- Option (A)

Explanation:

The pressure is often defined as the force per unit area. In the atmosphere, the pressure is maximum at the troposphere and is tightly packed near the ground surface. The troposphere is the region where the temperature decreases with the increasing height. The atmospheric pressure at sea level is nearly 1013.2 millibar (mb). The difference in the pressure in this layer causes the wind that is responsible for the occurrence of different types of weather patterns.

The earth and the sun maintains the shortest distance at its Perihelion position, which takes place in the month of January during the winter season in the northern hemisphere. And on the other hand, the earth is far away from the sun at its Aphelion position that takes place in the month of July.

Hence, the correct answers are given above.

7 0
3 years ago
When a tip of a plant is cut it doesn't grow well​
aleksandr82 [10.1K]

Explanation:

the tip of a growing plant contains special rapidly diving cells called apical meristem ,these cells are responsible for increase in the length of the plant . if we cut out these cells ,length growth of the plant will be stunned as these cells are not present anyplace else.

8 0
3 years ago
Read 2 more answers
Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
Anarel [89]

Answer:

The classification and illustrations are attached in the drawing.

Explanation:

It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.

On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.

4 0
3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
ANSWER FAST PLZZZ!!!!!!!!!!!!!
goldfiish [28.3K]

Answer:

1 and 2

Explanation:

1 is negative

2 is negative

3 is positive

5 0
3 years ago
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