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Snowcat [4.5K]
3 years ago
7

Which is a physical change?

Chemistry
1 answer:
kotykmax [81]3 years ago
3 0

Answer: Strawberries liquefied in a blender

Explanation:

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How is phosphorylation of glyceraldehyde 3-phosphate in the payment phase of glycolysis different from phosphorylation of glucos
svet-max [94.6K]

In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place.  During this phase, the conversion of glyceraldehyde-3-phosphate to pyruvate and the coupled formation of ATP take place. Because Glucose is split to yield two molecules of D-Glyceraldehyde-3-phosphate, each step in the payoff phase occurs twice per molecule of glucose.

Glyceraldehyde 3-phosphate dehydrogenase Simultaneous oxidation and phosphorylation of G3P produce 1,3-bisphosphoglycerate (1,3-BPG) and nicotine adenine dinucleotide (NADH).

The divalent cation also affected the response of the enzyme from the endosperm and shoots to adenine nucleotides and inorganic pyrophosphate.

This phase is also called the glucose activation phase. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. Steps 1, 2, 3, 4, and 5 together are called the preparatory phase.

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7 0
1 year ago
For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation?
KonstantinChe [14]

Answer:

Coefficient in front of the B_2H_6  in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

BF_3+NaH\rightarrow B_2H_6+NaF

On the left hand side,  

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,  

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,  

leftside, BF_3 must be multiplied by 2 to balance boron and right side, NaF must be multiplied by 6 to balance fluorine. Left side, NaH must be multiplied by 6 to balance sodium and hydrogen atoms.

Thus, the balanced reaction is:-

2BF_3+6NaH\rightarrow B_2H_6+6NaF

<u>Coefficient in front of the B_2H_6  in the balanced equation - 1</u>

6 0
3 years ago
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3 years ago
Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075
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7.5 is the answer. You have to move the decimal 2 places to the right.
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