<h3>
Answer:</h3>
3.01 × 10²⁵ molecules H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
50.0 mol H₂O
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u /> = 3.011 × 10²⁵ molecules H₂O
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.011 × 10²⁵ molecules H₂O ≈ 3.01 × 10²⁵ molecules H₂O
Answer:
the answer is 70.906 g/mol
Explanation:
Answer:
Mass = 64 g
Explanation:
Given data:
Mass of water produced = 36 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
CH₄ + 2O₂ CO₂ + 2H₂O
Number of moles of water produced:
Number of moles = mass/molar mass
Number of moles = 36 g/ 18 g/mol
Number of moles = 2 mol
Now we will compare the moles of water and oxygen.
H₂O : O₂
2 : 2
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 2 mol × 32 g/mol
Mass = 64 g