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3 years ago

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1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee

n them to be ___ the initial force

1 answer:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

Explanation:

For an electric force, F the formula:

F = kQq/r^2

Given:

r2 = 1/2 × r1

F1 × r1 = k

F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

= (F1 × r1^2)/0.25r1^2

= 4 × F1.

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Answer:

$\boxed{F_{net} = 28.7 \ N}$

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Explanation:

<u><em>Finding the net force:</em></u>

<u><em>Firstly , we'll find force of Friction:</em></u>

$F_{k} = (micro)_{k}mg$

Where $(micro)_{k}$ is the coefficient of friction and m = 13.6 kg

$F_{k} = (0.16)(13.6)(9.8)\\$

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<u><em>Now, Finding the net force:</em></u>

$F_{net} = F - F_{k}\\F_{net} = 50 - 21.32\\$

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<u><em>Finding Acceleration:</em></u>

$a = \frac{F_{net}}{m}$

$a = \frac{28.7}{13.6}$

$a = 2.1 \ m/s^2$

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