Explanation:
Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision
Step one
Analysis of the problem
Immediately after impact the car's velocity was zero making it a perfect elastic collision
Step two
Given
Mass of car M1=1800kg
Mass of truck M2=5200kg
Initial velocity of Car U1=44m/s
Initial velocity of truck U2=21m/s
Final velocity of car V1= 0m/s
Final velocity of truck V2=20m/s
Step three
According to the principle of conservation of momentum
Total momentum before collision
=M1U1+M2U2
Total momentum after impact
=M1V1+M2V2
M1U1+M2U2 =M1V1+M2V2
Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20
=66000+1218000=11600
1284000=11600
From the solution the momentum before impact is 1284000Ns
Momentum after impact is 11600Ns
This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero
Answer:
24000 kg·m/s
Explanation:
Momentum is Mass x Velocity, so 1200 kg time 20 m/s = 24000 kg-ms/s
Answer:
the number of grains in the ball is 274,848
Explanation:
Given that;
diameter = 0.5 mm
so radius r = 0.25 mm
first we determine the volume of the ball using the following equation;
V = 4/3×πr³
we substitute
V = 4/3×π(0.25)³
V = 0.06544 mm³
Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³
so;
Number of grains N = 0.06544 × 4,200,000
N = 274,848 grains
Therefore, the number of grains in the ball is 274,848
