All categories

3 years ago

Electrical resistance is measured in

2 answers:

8 0

Resistance is the ratio of

(voltage between two points in the circuit)
divided by
(current between the same points).

It's expressed in units of Ohms, so the correct choice is "none of the above".

My name is Ann [436]3 years ago

5 0

It's e. none of the above because electrical resistance is measured in ohms.

You might be interested in

How much weight can a man lift in the jupiter if he can lift 100kg on the earth.calculate

Nuetrik [128]

Answer:

<h3>2479 Newton</h3>

Solution,

Mass=100 kg

Acceleration due to gravity(g)=24.79 m/s^2

Now,.

 $weight = m \times g \\ \: \: \: \: \: \: \: \: \: \: = 100 \times 24.79 \\ \: \: \: \: \: \: = 2479 \: newton$ 

hope this helps ..

Good luck on your assignment..

5 0

3 years ago

4. Uncle Harry weighs 180 pounds. What is his mass in kilograms?

MatroZZZ [7]

180 pounds (lb) converts to 81.647 kilograms (kg).

5 0

2 years ago

A particle on a spring moves in simple harmonic motion along the x axis between turning points at x1 = 95 cm and x2 = 135 cm. (i

uranmaximum [27]

Answer:

(i) $x = 115\,cm$ , (ii) $x = 95\,cm$ , (iii) $x = 95\,cm$

Explanation:

(i) $x_{1}$ and $x_{2}$ represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:

$x = 115\,cm$

(ii) Maximum accelerations is reached at $x_{1}$ and $x_{2}$ .

$x = 95\,cm$

(iii) Greatest net forces exerted on the particle are reached at $x_{1}$ and $x_{2}$ .

$x = 95\,cm$

8 0

2 years ago

Two hockey pucks are sliding along the ice, towards the same goal, one directly in front of the other. The hockey puck in front

grandymaker [24]

Answer: A.9.2m/s

Explanation:

6 0

2 years ago

A railroad car having a mass of 17.5 Mg is coasting at 1.5 m/s on a horizontal track. At the same time another car having a mass

Leokris [45]

Answer:

Then final velocity of the coupled system of cars will be 0.58 m/s

Explanation: Let us consider the car-1 is moving towards right (say + ve direction) and car-2 is moving towards left (say in - ve direction), accordingly velocity are considered +ve and -ve.

$m_{1} = 17.5 \ Mg = 17.5 \times 10^{6} \ g = 17.5 \times 10^{3} \ Kg = 17500 \ Kg$