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Eduardwww [97]
3 years ago
12

In the following description, QUOTE the portion that addresses weather in the area.

Physics
1 answer:
olga nikolaevna [1]3 years ago
4 0

Answer:

Portland normally had rainy, but mild winters. Yesterday it rained 0.75 inches in Portland.

Explanation:

This talks about the weather

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Suppose a Southwest Airlines passenger plane took three hours to fly 1800 miles in the direction of the Jetstream. The return tr
Alex73 [517]

Answer:

plane speed: 525mph, jetstream speed=75mph, in explanation it is solved with a linear equations system

Explanation:

First lets name each speed

vs:=speed of the jetstream

vp:=speed of the plane

Now when in the jetstream direction the speeds are added and on the opposite direction are subtracted, then we get these equations, that are linear.

1800 mi=(vp+vs)*3h

1800 mi=(vp-vs)*4h

which is a linear equation system equivalent to:

600 mph=vp+vs (1)

450 mph=vp-vs  (2)

Now from (2) vp= 450mph+vs (3), replacing this in (1) we get:

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7 0
4 years ago
The greater force is applied the the acceleration
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<span>Newton's 1st Law of Motion is also known as the Law of. ... Newton's 2nd Law says that when an is applied to a  it causes it to  Newton's 2nd Law says that when an UNBALANCED FORCE is applied to a MASS, it causes it to ACCELERATE. The greater the force that is applied, the the acceleration.</span>
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3 years ago
What force must be provided to accelerate a 64-lb object upward at a rate of 2 ft/s2? (Use g = 32 ft/s2.)
vovikov84 [41]

Answer:

The force that must be provided to accelerate the object = 302.196 N

Explanation:

<em>Force</em>: Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).

Ft - W = ma............ Equation 1

Ft = W + ma .......... Equation 2

Where Ft = force provided, W = weight of the object, m= mass of the object, a = acceleration of the object.

<em>Given: mass = 64 lb, g = 32 ft/s² a = 2 ft/s²</em>

<em>Conversion: (i)  from 64 pounds to Kg = 64/2.2046</em>

<em>                       = 29.03 kg</em>

<em>   (ii)  from 2 ft/s² to m/s² = 0.3048 × 2 = 0.6098 m/s²</em>

<em> (iii) from 32 ft/s² to m/s² = 0.3048×32 = 9.8 m/s².</em>

and W = mg = 29.03 × 9.8 = 284.494 N,

Substituting these values into equation 2,

Ft = 284.494 + 29.03×0.6098

Ft = 284.494 + 17.7

Ft = 302.196 N

Therefore, the force that must be provided to accelerate the object = 302.196 N

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A 2.90 kg mass is pushed against a horizontal spring of force constant 23.0 n/cm on a frictionless air table. the spring is atta
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