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4 years ago

How many 1/5s make 14/10?

Mathematics

2 answers:

nydimaria [60]4 years ago

8 0

There are 1/5 goes into 14/10 seven times

tatiyna4 years ago

3 0

Answer:

seven ( 7 ) number of 1/5s make 14/10

Step-by-step explanation:

To find the numbers of 1/5s that make 14/10, we will simply divide 14/10 by 1/5, thus;

14/10 ÷ 1/5

We can change the division into myltiplication by taking the inverse of 1/5.

Not that inverse of 1/5 is 5/1 = 5

Hence;

$\frac{14}{10}$ × 5

5 can divide 10 at the denominator 2 times.

Hence ;

$\frac{14}{2}$

14 divide by 2 will give us 7.

Therefore, the number of 1/5s that make 14/10 are seven (7)

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2 years ago

Read 2 more answers

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

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