SOH,CAH, TOA so it would be TANGENT since it would be Opposite over Adjacent. Tan(15) = 9/a put Tan(15) onto your calculator it would be .267949 round that to .27 = 9/a cross multiply
a = 33.588. C is the correct answer.
X by its self is always 1x
1x+8=-15 you have to get rid of 8 by subtracting on both sides
1x=-23 now get rid of 1 by dividing on both sides
x=-23
Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Part 5)
Part 6) The graph in the attached figure
Step-by-step explanation:
Part 1) we have


The equation of the line into point slope form is equal to

substitute



Part 2) we know that
If two lines are perpendicular
then
the product of their slopes is equal to minus one
so

the slope of the line 1 is equal to

Find the slope m2


Find the equation of the line 2
we have


The equation of the line into point slope form is equal to

substitute



Part 3) we have

The equation of the line into point slope form is equal to

substitute



Part 4) we have

-----> y-intercept
we know that
The equation of the line into slope intercept form is equal to

substitute the values

Part 5) we have that
The slope of the line 4 is equal to 
so
the slope of the line perpendicular to the line 4 is equal to

therefore
in this problem we have


The equation of the line into point slope form is equal to

substitute



Part 6)
using a graphing tool
see the attached figure
Answer:
900
Step-by-step explanation:
perimeter: P = 2w + 2h
P = 2(20) + 2(25)
P = 40 + 50
P = 90
Multiply perimeter by 10:
90 × 10 = 900
Answer:
Choice A
1/17; no, they are dependent events
============================================
Explanation:
There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade
If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total.
Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17
The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.