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Ket [755]
3 years ago
13

Always, sometimes or never true: The sum of a positive integer and negative integer is positive.

Mathematics
2 answers:
marta [7]3 years ago
7 0
This would be always true because the positive number would cancel the negative number out.
o-na [289]3 years ago
4 0

Answer:

sometimes true ( hopefully I am right)

Step-by-step explanation:

Adding two positive integers always gives you a positive sum; adding two negative integers always gives you a negative sum so find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract those values.

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Can someone double check my work for this problem? I got 38°??
scoundrel [369]
We need to use Law of sine.

sin A/a = sin C/c
sin A/|CB| = sin C/|AB|

sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20

A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰
4 0
3 years ago
a group of 60 children went on a trip to the zoo 7/10 of the children had never been there how many children went to the zoo for
zvonat [6]

Answer:

42

Step-by-step explanation:

as you divide 10 into 60 and then multiply it by 7 and your answer will be 42

5 0
2 years ago
What’s the difference quotient simplified
mihalych1998 [28]

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

7 0
3 years ago
I need help on iready
kicyunya [14]

Answer:

the answer is 3

Step-by-step explanation:

because if you do the methoes method you know that it rules out 1 and 2 after you do that its just between 3 and 4, for the caunususicon there has to be one, that is why i think its 3. hope this helps!

7 0
3 years ago
Rewrite 7x^5/2 in simplest radical form
Diano4ka-milaya [45]

Answer:

7x²sqrt(x)

Step-by-step explanation:

7x^(5/2)

7x^(2½)

7x^(2+½)

7x² × x^½

7x²sqrt(x)

sqrt: square root

4 0
3 years ago
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