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MrRissso [65]
4 years ago
9

Noelle ran 4 1/2 miles in the morning and 3 1/4 miles in the evening. How far did Noelle run that day?

Mathematics
1 answer:
KIM [24]4 years ago
6 0
You just add all the numbers together:
3 1/8+ 4 1/2+ 4 1/4
=25/8+9/2+17/4
=25/8+36/8+34/8
=95/8
=11 7/8

Ugh.. did you type in the numbers correctly? My guess would be it was meant to be B tho :)

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garik1379 [7]

Answer:

How generous of you~

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Step-by-step explanation:

7 0
3 years ago
L || m
Alona [7]

Answer:

c. m∠1 + m∠6 = m∠4 + m∠6

Step-by-step explanation:

Given: The lines l and m are parallel lines.

The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.

a.  m∠1 + m∠2 = m∠3 + m∠4

Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.

m∠3 and  m∠4 are supplementary angles add upto 180 degrees.

Therefore, the statement is true.

b. m∠1 + m∠5 = m∠3 + m∠4

m∠1 + m∠5 = 180 same side of the adjacent angles.

m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.

Therefore, the statement is true.

Now let's check c.

m∠1 + m∠6 = m∠4 + m∠6

We can cancel out m∠6, we get

m∠1 = m∠4 which  is not true

Now let's check d.

m∠3 + m∠4 = m∠7 + m∠4

We can cancel out m∠4, we get

m∠3 = m∠7, alternative interior angles are equal.

It is true.

Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6

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3 years ago
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kolbaska11 [484]
<h3>Answer: B. (40,40)</h3>

Explanation:

<u>Given Inequalities</u>:

(i) 3x + 8y ≤ 480

(ii) y - x ≤ 20

For first inequality:

(a) y intercept: (0, 60)

(b) x intercept: (160, 0)

  • Plot this line with a solid line and shade below.

For second inequality:

(a) y intercept: (0, 20)

(b) x intercept: (-20, 0)

  • Plot this line with a solid line and shade below.

The point (40, 40) falls between these two inequalities.

3 0
2 years ago
I need help on this pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
victus00 [196]

Answer:

Step-by-step explanation:

1). From the graph attached,

  Price of one ticket last year = $1.5

  From the table attached,

  Price of one ticket this year = $2

  Therefore, price of one ticket this year is higher than the last year.

  This year ticket is expensive.

2). From the graph attached,

   Price of 4 tickets last year = $6

3). Since, price of one ticket this year = $2

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8 0
3 years ago
Read 2 more answers
I need help plz. Its DeMoivres Theorem
vagabundo [1.1K]

\bf \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ z=\stackrel{a}{-1}\stackrel{b}{-\sqrt{3}~i}~~ \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right)\\[-0.5em] \hrulefill\\ r=\sqrt{(-1)^2+(\sqrt{3})^2}\\ \qquad \sqrt{4}\\ \qquad 2\\ \theta =tan^{-1}\left( \frac{-\sqrt{3}}{-1} \right)\\\\ \qquad \frac{4\pi }{3} \end{cases}

\bf z=2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right]\implies z^6=\left[ 2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right] \right]^6 \\\\\\ z^6=2^6\left[ cos\left( 6\cdot \frac{4\pi }{3} \right) -i~sin\left( 6\cdot \frac{4\pi }{3} \right)\right]\implies z^6=64[cos(8\pi )-i~sin(8\pi )] \\\\\\ z^6=64[(-1)-i~(0)]\implies z^6=\stackrel{\stackrel{a}{\downarrow }}{-64}~~\stackrel{\stackrel{b}{\downarrow }}{-0i}

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4 years ago
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