All categories

3 years ago

HELP IF YOU'RE GOOD AT GEOMETRY

Mathematics

1 answer:

Jet001 [13]3 years ago

8 0

Answer:

corresponding angles- 4 and 8, 3 and 7, 1 and 5, 2 and 6

same side interior angles- 2 and 5, 3 and 8

alternate interior angles- 3 and 5, 2 and 8

alternate exterior angles- 1 and 7, 4 and 6

Step-by-step explanation:

You might be interested in

You have $3000 to enclose a rectangular piece of property with a fence. The fence costs $9 per foot. A scale drawing of the prop

son4ous [18]

Answer:

Step-by-step explanation:

C=9P

P=2(L+W)

C=18(L+W)

C=18(8(12)+7(12))

C=18(96+84)

C=18(180)

C=$3240

So you do not have enough money to enclose the property.

8 0

2 years ago

Find a degree 3 polynomials with real coefficient having zeros 2 and 4i and a leading coefficient of 1. Write P in expanded form

Gelneren [198K]

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

7 0

3 years ago

Let sin(−θ)=−3/5 and tanθ>0. What is the value of cos(−θ)?

Jobisdone [24]

Answer:

The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = $\frac{- 3}{5}$

- sin Ф = $\frac{- 3}{5}$

So, sin Ф = $\frac{ 3}{5}$

Now, as sin Ф = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

So , $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$ = $\frac{ 3}{5}$

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴ Base = $\sqrt{16}$

I.e Base = 4

Now, Cos Ф = $\dfrac{\textrm base}{\textrm hypotenuse}$

So, Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Now , Since

Cos ( - Ф ) = Cos Ф

So, Cos ( - Ф ) = Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Hence The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ . Answer

6 0

2 years ago

Which equation represents y = −x2 + 6x + 7 in vertex form? y = −(x + 3)2 + 4 y = −(x − 3)2 + 10 y = −(x + 3)2 + 2 y = −(x − 3)2

Colt1911 [192]

$\text{The vertex form:}\ y=a(x-h)^2+k\\\\f(x)=ax^2+bx+c\to h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have}\ y=-x^2+6x+7\to f(x)=-x^2+6x+7\\\\a=-1,\ b=6,\ c=7\\\\h=\dfrac{-6}{2(-1)}=\dfrac{-6}{-2}=3\\\\k=f(3)=-3^2+6(3)+7=-9+18+7=16\\\\Answer:\ \boxed{y=-(x-3)^2+16}$

8 0

3 years ago

4 0ver 6 + 5 0ver 12

Elis [28]

Answer:

1.083

Step-by-step explanation:

7 0

2 years ago