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Simora [160]
3 years ago
6

"Write a related multiplication sentence that could help you find the quotient of 6 divided by 1/4."

Mathematics
2 answers:
kogti [31]3 years ago
8 0
.25x6=2
if you need it in word format
point twenty five times six equals two
Pani-rosa [81]3 years ago
6 0
6 x 4 is the same as 6 divided by 1/4.
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<span>If the half-life of the drug is 2 hours, then in 2 hours 0.6 mg of the drug becomes 0.3 mg. In two more hours (4 hours total) it is 0.15 mg, 2 more hours (6 hours) .075 mg. In two more hours (8 hours) it is .0375 mg, rounded to 0.04. The answer is 8 hours.</span>
3 0
3 years ago
Someone help me with this pleaseee..
Blababa [14]

So whatever happened does not matter, They are only asking the volume of liquid left in A at the end. Therefore :

Calculation :

B + 120 = 4A

B = 4A - 120 ---------- 1

A - 120 = B ------------ 2

Subtract 2 from 1

B - B = 4A - 120 - A - 120

0 = 3A - 240

240 = 3A

240 ÷ 3 = A

8 = A

Answer :

A = 8

3 0
3 years ago
Which of the following statements is true?
Hitman42 [59]
If my memory serves me well, the only wtatement which is true is the last one: <span>D) All linear equation and all quadratic equations are polynomial equations.</span>
8 0
3 years ago
Read 2 more answers
How would I rewrite this?
Anvisha [2.4K]

Answer:

-The answer is y^2 .

Step-by-step explanation:

When you divide numbers/variables with exponents, the exponents will subtract each other:

\frac{y^5}{y^3} =y^2

8 0
4 years ago
What is a cubic polynomial function in standard form with zeroes 1, –2, and 2?
Lisa [10]
Starting off with the polynomial in standard form would be extremely difficult, but we can construct one fairly easily with the zeroes we've been given.

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Notice that we can easily obtain each our three zeroes by dividing both sides by the two other factors. From here, we just need to expand the left-hand side of the equation. I'll show the work required here:

(x-1)(x+2)(x-2)=0\\&#10;\big[(x-1)x+(x-1)2\big](x-2)=0\\&#10;(x^2-x+2x-2)(x-2)=0\\&#10;(x^2+x-2)(x-2)=0\\&#10;(x^2+x-2)x-(x^2+x-2)2=0\\&#10;x^3+x^2-2x-(2x^2+2x-4)=0\\&#10;x^3+x^2-2x-2x^2-2x+4=0\\&#10;x^3+(x^2-2x^2)+(-2x-2x)+4=0\\&#10;x^3-x^2-4x+4=0\\

So, in standard form, our cubic polynomial would be x^3-x^2-4x+4
3 0
4 years ago
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